RyanSF07 Posted February 15, 2007 Share Posted February 15, 2007 Hi All, Thanks for your help during these past couple days. I'm enjoying this forum. I've run into trouble with php/mysql for editing a quiz question in an esl quiz app. In the 'edit quiz' pages of this app, one page identifies all of the question of a quiz built by a particular registered user. From this page the user can select a question to edit. (Works great) The user is then taken to a page where the question form is populated. Here is the code for that: <?php $id = $_GET['id']; $update = $_POST['update']; $question = $_POST['question']; $opt1 = $_POST['opt1']; $opt2 = $_POST['opt2']; $opt3 = $_POST['opt3']; $answer = $_POST['answer']; if($id) { $sql = "SELECT * FROM $table WHERE id=$id"; $query_result = mysql_query($sql); $myrow = mysql_fetch_array($query_result); ?> Edit this question.<?echo "$_GET[id] $id $_SESSION[get]";?> <form method="post" name="update" action="editquiz_updateQ_processor.php?$_GET[id];"> <input type="hidden" name="id" value="<?php echo $myrow[id]?>"> <b>Question:</b><br> <input type="Text" name="question" value="<?php echo $myrow[question]?>" size="50"> <br> <b>Option 1:</b><br> <input type="Text" name="opt1" value="<?php echo $myrow[opt1]?>" size="30"> <br> <b>Option 2:</b><br> <input type="Text" name="opt2" value="<?php echo $myrow[opt2]?>" size="30"> <br> <b>Option 3:</b><br> <input type="Text" name="opt3" value="<?php echo $myrow[opt3]?>" size="30"> <br> <b>Answer</b> (must be identical to correct option):<br> <input type="Text" name="answer" value="<?php echo $myrow[answer]?>" size="30"> <br> <br> <input type="Submit" name="update" value="Update information"></form> <? } ?> Note, this code is working and echoing the id's produces the correct values. The third page is the 'processor.' It is meant to take the data and insert it into the quiz table. On all of the other pages I'm made for notes, title, by, transcript, etc, this works. On this page, however, with this code.. nothing works. I've tried so many suggestions that my eyes are missing something. Please look this part over and point out my mistake. Thank you very much for your time and help <?php $id = $_GET[id]; $update = $_POST[update]; $question = $_POST[question]; $opt1 = $_POST[opt1]; $opt2 = $_POST[opt2]; $opt3 = $_POST[opt3]; $answer = $_POST[answer]; if ($_POST[update]) { $query = "UPDATE quiz SET question = '$question', opt1='$opt1', opt2='$opt2', opt3='$opt3', answer='$answer' WHERE id='$id'"; $result = mysql_query($query); echo "Update is successful! Thank You";} else{ echo "Failed updating: " . mysql_error() . "\n$sql\n"; } ?> In testing, this last part fails to work. The app reports "Upate is successful! Thank You" , but the update did not in fact occure. Looking forward to hearing from you. Ryan Quote Link to comment https://forums.phpfreaks.com/topic/38584-solved-update-trouble-new-take/ Share on other sites More sharing options...
btherl Posted February 15, 2007 Share Posted February 15, 2007 What do you get if you add echo $query ? That should help to show what's going wrong. Also, your failed clause in the second script uses $sql, but the query is called $query. That doesn't make a difference now, but would if the query failed Quote Link to comment https://forums.phpfreaks.com/topic/38584-solved-update-trouble-new-take/#findComment-185222 Share on other sites More sharing options...
RyanSF07 Posted February 15, 2007 Author Share Posted February 15, 2007 Thanks a lot btherl! Following your advice showed me were the error was, and I fixed it. Now all works wonderfully. Thanks again Ryan Quote Link to comment https://forums.phpfreaks.com/topic/38584-solved-update-trouble-new-take/#findComment-185508 Share on other sites More sharing options...
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