Basic array using end and while

[suttercain]

Hello and good weekend!

 

I am reading a PHP book and in one of the tutorials that deals with arrays they provid the following code:

 

<?php
$numbers = array("one", "two", "three", "four");
$item = current($numbers);
do
{
echo "$item ";
}
while (($item = next($numbers)) !== FALSE);
echo "<br/> \n";
end($drinks);
while (($item = prev($drinks)) !== FALSE)
{
echo "$item<br/>\n";
}
?>

 

When I run it locally on my apache server I get the following:

 

one two three four

 

Warning: end() [function.end]: Passed variable is not an array or object in D:\wamp\www\PHP Tutorials\arrays.php on line 10

 

Warning: prev() [function.prev]: Passed variable is not an array or object in D:\wamp\www\PHP Tutorials\arrays.php on line 11

 

When it actually shoud print:

 

one two three four

four three two one

 

 

Where is the error? Thanks in advance.

 

Shannon

[printf]

There is no array() called $drinks! So how can end(); move to the last key, if the array doesn't exist!

 

printf

[LazyJones]

pretty sure it should be end($numbers)....

 

no more drinks for you!

[suttercain]

Good looking out. For anyone interested: That mistake is on page 123 of "Web Application and Development  with PHP and MYSQL"

 

Thanks.