ignore a statement

[elis]

I have the following code:

 

if(!$username==""){
$qCheck = "select * from ....

(I didn't put the full code, because I didn't think it was vital - if anyone thinks it is let me know, and I'll add it.)

 

($username is a $_post[...] field from an input box)

 

Which is for if the $username field isn't empty, to run a a check on it and output a specific result.

However, when the $username field is empty, the script stops running. Is there any way I can get the script to ignore if the $username field is empty, and continue running?

[nloding]

You'll have to post the code after the IF statement.

 

You can either take out the IF statement, or there isn't anything after the IF statement to parse when the username is empty.  If there is code after the IF statement, that should process if the username is blank.

[JBS103]

if(!$username==""){
$qCheck = "select * from ....

 

To begin with I would use either

 

if(isset($username))

or

if($username != "")

 

The way you have it seems convoluted to me. But now, if you want it to run, when the $username has a value, put the code inside the If. If you want it to do nothing when the $username is blank, than just put the next step of code outside of the If, similar to what nloding was saying.

[nloding]

There's a million different ways to do it, all with the same result.  Personally, in the IF statement, I would put what happens if $username doesn't exist, and have the rest of the code as the else, because usually there's more code if it exists.

 

if(!$username) {
}else{
}

//or 

if(empty($username)) {
}else{
}