suttercain Posted February 28, 2007 Share Posted February 28, 2007 Hello, I have an array via the MySQL database. The column I am working with is fuels and the fields are "GN11," "NN01." and "DC03". I need them to echo as GN11=>GASOLINE, NN01=>CNG, DC03=>DIESEL. Here is the code I am using (I also used it for vehicles and it worked), but the output isn't changed: // Convert the Array FUEL to FUEL TYPE $fuel_types = array('GN11'=>'GASOLINE', 'NN01'=>'CNG', 'DC03'=>'DIESEL'); print $fuel_types[$row['fuel']]; echo "<td width='60'><font size=1.5>$row[fuel]</font></td>\n"; So the output I am getting is Still GN11 instead of GASOLINE. Where am I going wrong? Thank you in advance. Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/ Share on other sites More sharing options...
itsmeArry Posted February 28, 2007 Share Posted February 28, 2007 use this:: echo "<td width='60'><font size=1.5>$fuel_types[$row[fuel]]</font></td>\n"; Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/#findComment-196217 Share on other sites More sharing options...
suttercain Posted February 28, 2007 Author Share Posted February 28, 2007 Thanks for responding, I added: echo "<td width='60'><font size=1.5>$fuel_types[$row[fuel]]</font></td>\n"; and replaced: echo "<td width='60'><font size=1.5>$row[fuel]</font></td>\n"; But I am getting the following parse error: Parse error: parse error, unexpected '[', expecting ']' in C:\wamp\www\ARB\pio\2007ccvl.php on line 131 I don't know why... Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/#findComment-196223 Share on other sites More sharing options...
boo_lolly Posted February 28, 2007 Share Posted February 28, 2007 change $row[fuel] to $row['fuel'] Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/#findComment-196226 Share on other sites More sharing options...
redarrow Posted February 28, 2007 Share Posted February 28, 2007 <?php echo "<td width='60'><font size=1.5>".$row['fuel']."</font></td>\n"; ?> Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/#findComment-196227 Share on other sites More sharing options...
suttercain Posted February 28, 2007 Author Share Posted February 28, 2007 Thanks for responding, I tried: echo "<td width='60'><font size=1.5>".$row['fuel']."</font></td>\n"; And it still echoed GN11 instead of GASOLINE I also tried adding ' ' around fuel: echo "<td width='60'><font size=1.5>$fuel_types[$row['fuel']]</font></td>\n"; and still got the parse error listed above. I am not sure why it isn't working... From the looks of it, it should be running. Any other suggestions? Thanks. Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/#findComment-196232 Share on other sites More sharing options...
suttercain Posted February 28, 2007 Author Share Posted February 28, 2007 I got it: I changed the line of code to: echo "<td width='60'><font size=1.5>".$fuel_types[$row['fuel']]."</font></td>\n"; Thanks guys for getting me on the right track. Shannon Quote Link to comment https://forums.phpfreaks.com/topic/40548-solved-database-array-with-alternative-output/#findComment-196242 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.