Write PHP Output Back to Form Textbox

supratwinturbo · March 1, 2007

Hi All,

I have a web form composing of textboxs for users to enter numbers into. After they press submit, I have a php script that processes the numbers and now echos back the output onto the page. I would like the php output to "echo" into a textbox of the form. How can I do this? Any help would be greatly appreciated.

Thank you.

scottybwoy · March 1, 2007

It depends on how you are generating the page. If your page comes from the .php file then it is slightly easier as you can just do...

<?php
$numbers1 = $_POST['numbers1'];
$numbers2 = $_POST['numbers2'];
?>
<form method="POST">
<label for="n1">Numbers #1 :</label><input type="text" id="n1" name="numbers1" value="<?php echo $numbers1; ?>" /></br>
<label for="n2">Numbers #2 :</label><input type="text" id="n2" name="numbers2" value="<?php echo $numbers2; ?>" /></br>
</form>

Or if you are using templates, you will need to flag up the globals scope, i.e.

<?php
globals $numbers1, $numbers2;

$numbers1 = $_POST['numbers1'];
$numbers2 = $_POST['numbers2'];

include(form.php);
?>

But without any more info, that's as far as I can help you, what is it exactly you are trying to do?

supratwinturbo · March 2, 2007

Hi Scotty,

Here is an example of what I am trying to do:

<head>
<title>Year/Age Calculator</title>
</head>
<body>

<form action="<?php echo($_SERVER['PHP_SELF']); ?>" method="GET">
<label for="Age">Age :</label><input type="text" id="n1" name="age" value="<?php echo $age; ?>" /></br><br>
<label for="Year">Year Born :</label><input type="text" id="n2" name="year" value="<?php echo $year; ?>" /></br><br>
<input type="submit" name="YearBorn" value="Find Year Born" />
<input type="submit" name="FindAge" value="Find Your Age" />
</form>

<?php

$age = $_GET["age"];
$year = $_GET["year"];

$YearBorn = $_GET["YearBorn"];
$FindAge = $_GET["FindAge"];

if(isset($YearBorn))
{
$year = 2007 - $age;
echo "Year Born = $year";
}

if(isset($FindAge))
{
$age =  2007 - $year;
echo "Your Age = $age";
}

?>

</body>
</html>

So in the above code, there are two textboxes, one for entering a person's Age and one for entering a person's Year of Birth. For example, if I enter 30 into the Age TextBox, I would click on the "Find Year Born" button and the php script will return the year born which will be 2007-30 = 1977. Right now the code just echos the year born onto the screen. I would like it to echo the output into the Year Born Textbox instead. So Basically, if I enter a number into the Age Textbox and Click on "Find Year Born" button, the answer will appear in the Year Born Textbox. On the other hand, if I enter a number into the Year Born Textbox and Click on "Find Your Age" button, the answer will appear in the Age Textbox. I hope I made my question clearer and that you or someone can help me.

Thank you.

itsmeArry · March 2, 2007

use it like this


<?php
$age = '';
$year = '';

$FindAge ='';
$YearBorn ='';

if(isset($_GET["age"]))
     $age= $_GET["age"];

if(isset($_GET["Year"]))
     $Year= $_GET["Year"];

if(isset($_GET["FindAge"]))
     $FindAge = $_GET["FindAge"];

if(isset($_GET["YearBorn"]))
     $YearBorn = $_GET["YearBorn"];


if(isset($YearBorn))
{
$year = 2007 - $age;
echo "Year Born = $year";
}

if(isset($FindAge))
{
$age =  2007 - $year;
echo "Your Age = $age";
}

?>


<form action="<?php echo($_SERVER['PHP_SELF']); ?>" method="GET">
<label for="Age">Age :</label><input type="text" id="n1" name="age" value="<?php echo $age; ?>" /></br><br>
<label for="Year">Year Born :</label><input type="text" id="n2" name="year" value="<?php echo $year; ?>" /></br><br>
<input type="submit" name="YearBorn" value="Find Year Born" />
<input type="submit" name="FindAge" value="Find Your Age" />
</form>

supratwinturbo · March 6, 2007

Hi itsmeARRY,

Thank you for the help. I had to modify your code to get it to work, but you pointed me in the right direction. Here is the code I used:

<head>
<title>Year/Age Calculator</title>
</head>
<body>

<?php
$age = '';
$year = '';

$FindAge ='';
$YearBorn ='';
$Operation=$_GET["Operation"];

if(isset($_GET["age"]))
     $age= $_GET["age"];

if(isset($_GET["year"]))
     $year= $_GET["year"];

if(isset($_GET["FindAge"]))
     $FindAge = $_GET["FindAge"];

if(isset($_GET["YearBorn"]))
     $YearBorn = $_GET["YearBorn"];

if($Operation == "YearBorn")
{
$year = 2007 - $age;
}
else
if($Operation == "FindAge")
{
$age =  2007 - $year;
}

?>

<form action="<?php echo($_SERVER['PHP_SELF']); ?>" method="GET">
<label for="Age">Age :</label><input type="text" name="age" value="<?php echo $age; ?>" /></br><br>
<label for="Year">Year Born :</label><input type="text" name="year" value="<?php echo $year; ?>" /></br><br>
<input type="submit" name="Operation" value="YearBorn" />
<input type="submit" name="Operation" value="FindAge" />
</form>

</body>
</html>

I am now trying to make the form remember which color (a select list) they selected before pressing any of the submit buttons. I entered this code into the form:

<select name="color">
<option value="red">red</option>
<option value="blue">blue</option>
</select></br>><br>

For example, if the user selects blue and then clicks on either one of the "submit" buttons, I want the form to remember/show the blue option. Right now the select list always goes back to red, the first choice. I tried doing a <?php echo $red; ?> and <?php echo $blue; ?> for the option value, but this does not work since the select list needs a value.

Thank you.

gavinandresen · March 7, 2007

I wrote a function "fillInFormValues()" that makes this kind of thing easy.

You put the form in a PHP string:

$formHTML =<<<FORM_END

<form....>

... all the form stuff...

</form>

FORM_END;

And then you call:

$filledInHTML = fillInFormValues($formHTML, $_GET);

... and magic happens. Your <selects> will be selected properly (based on what's in $_GET), your checkboxes will be checked properly...

Grab it from: http://www.skypaint.com/gavin/code/

(online examples are there, too).

supratwinturbo · March 7, 2007

Hi Gavinandresen,

Congratulations on the wonderful php function you have created. However, I wish to learn how to solve my problem with some basic php code that I can understand...I tried looking at how your code works and I am lost....sorry I am a total newbie to this. If it is possible can you please explain to me how to make php remember which <select> a user clicked?

Thank you.

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Write PHP Output Back to Form Textbox

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