Jump to content

[SOLVED] mysql_fetch_array


adamh91

Recommended Posts

Hey, I'm getting this error in my code:

 

 Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/r3v/public_html/scripts/includes/emails.php on line 40

 

I was wondering if its an error in my code, i cannot see any, or i have chmodded it incorrectly.

 

<?
include 'config.php';

$i = 1;
//---Display Emails---\\

$conn = mysql_connect($db_host, $db_user, $db_pass) or die ('Error: '. mysql_error());
mysql_select_db($db_name);
$sql = "SELECT email FROM emails";
$res = mysql_query($sql);
while($row = mysql_fetch_array($res)){

if ($i == 1) {  
echo '<tr valign="top">';
echo '<td width="100%" bgcolor="#0098CC" class="alt1">'.$row['email'].'</td>';
echo '</tr>';
$i = 2;
} else {
echo '<tr valign="top">';
echo '<td width="100%" bgcolor="#00A6DA" class="alt1">'.$row['email'].'</td>';
echo '</tr>';
$i = 1; }

} 
mysql_free_result($res);
mysql_close($conn);
//---End Display---\\
?>

Link to comment
https://forums.phpfreaks.com/topic/40726-solved-mysql_fetch_array/
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.