Help with IF statment

[solgun]

how can i make an if clause find if a variable is like "first letter"?

i want to divide all shown result form a search... when the user choose one letter it shows only result starting with that letter

something like

if ($result LIKE 'a%') {

thing happens }

 

Thank you  

[AV1611]

you need to do a regex but I'm lousy at them

 

[idevlabsdotcom]

if(substr($result, 0, 1) == "a"){
 //result starts with the letter a
}

or you could use regular expressions:

if(eregi("^a", $result)){
 //result starts with the letter a
}

[solgun]

Thank you very much 

 

one love

[danrah]

you can use this regex pattern :

/a*?/

 

$regex="/a*?/";
if(preg_match($regex,$result)){
//do something
}