[SOLVED] only adding one.

[grlayouts]

The script below should insert into the database one factory on the drop down as long as the player has cash. However its only working on the drug one not the steak house.

 

any idea's?

 

<? print "<form method=post action=enterprises.php?view=add&step=add>Build  <select name=building><option value=DrugFactory>Drug Factory</option><option 	value=SteakHouse>Steak House</option><option 	value=CarLot>Car Lot</option><option 	value=Passport>Passport</option></select>. <input type=submit value=Add></form>";
if ($step == add) {
if ($building == 'DrugFactory') {
if ($stat[credits] <30000) {
print "Sorry mate, you don't have the cash.";
} else {
	mysql_query("update players set drugfact=drugfact+1 where id=$stat[id]");
		print "Building added."; }}}
	 else {
if ($building == 'SteakHouse') {
if ($stat[credits] <60000) {
print "Sorry mate, you don't have the cash.";
} else {
	mysql_query("update players set steakhouse=steakhouse+1 where id=$stat[id]");
		print "Building added."; }}}?>

[JBS103]

What should $step equal when you want to add a steakhouse? Is the program outputting anything when you try to make a new steakhouse?

[grlayouts]

what?

[JBS103]

Does the screen show either "Sorry mate, you don't have the cash." or "Building added." when you try to make a steak house, or is the screen blank?

[LazyJones]

Your statements (opening and closing curly brackets) are a bit messed up:

 

that code will never enter to checking for 'steakhouse' if the $step == 'add'

 

btw. using e.g. switch-case statement would be cleaner and you would better avoid errors like such

 

 

[grlayouts]

Does the screen show either "Sorry mate, you don't have the cash." or "Building added." when you try to make a steak house, or is the screen blank?

 

i get nothing..

 

what would you suggest?

[JBS103]

Does the screen show either "Sorry mate, you don't have the cash." or "Building added." when you try to make a steak house, or is the screen blank?

 

i get nothing..

 

what would you suggest?

What LazyJones suggested seems right. Thats why I asked what you expected the $step variable to equal when you wanted to add a steakhouse, because he is right, it will never get down there if $step == add

[grlayouts]

ermm ok, i still have no idea how to do it.

[JBS103]

<?php
print "<form method=post action=enterprises.php?view=add&step=add>Build  <select name=building><option value=DrugFactory>Drug Factory</option><option 	value=SteakHouse>Steak House</option><option 	value=CarLot>Car Lot</option><option 	value=Passport>Passport</option></select>. <input type=submit value=Add></form>";
if ($step == "add") 
{
switch($building)
{
	case "DrugFactory":
		if ($stat[credits] < 30000) {
			print "Sorry mate, you don't have the cash.";
		} else {
			mysql_query("update players set drugfact=drugfact+1 where id=$stat[id]");
			print "Building added."; 
		}
	break;
	case "SteakHouse":
		if ($stat[credits] < 60000) {
			print "Sorry mate, you don't have the cash.";
		} else {
			mysql_query("update players set steakhouse=steakhouse+1 where id=$stat[id]");
			print "Building added."; 
		}
	break;
}
}
?>

Try something like that

[grlayouts]

perfect. your the man.