TRI0N Posted March 4, 2007 Share Posted March 4, 2007 Okay my function addMe works great but my isType is throwing a fit. <script type="text/javascript"> function addMe(){ v1=document.getElementById("val1").value v2=document.getElementById("val2").value v3=Number(v1) * Number(v2) document.getElementById("tot").innerHTML=v3 ; } function isType(){ if (document.getElementById("type").value == "Team") { v4=document.getElementById("ts").value v5=Number(v3) / Number(v4) document.getElementById("nt").innerHTML=v5 ; } } </script> Any help would be great! Link to comment https://forums.phpfreaks.com/topic/41081-getting-an-error/ Share on other sites More sharing options...
paul2463 Posted March 4, 2007 Share Posted March 4, 2007 where is v3 declared in your isType() function??? function isType(){ if (document.getElementById("type").value == "Team") { v4=document.getElementById("ts").value v5=Number(v3) / Number(v4) --> v3 is not declared or defined in this function document.getElementById("nt").innerHTML=v5 ; } } Link to comment https://forums.phpfreaks.com/topic/41081-getting-an-error/#findComment-199043 Share on other sites More sharing options...
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