A popup Window?

[rameshfaj]

I have a database with entries like:itemid,itemname,itempicture,itemstock,...etc.

 

I have displayed the itemid,itempicture on the PHP pages.

Now what i want is that when the user clicks on the image of the item,the other informations about the item(selected from the database )should be displayed in the popup window.

 

I am using PHP for the serverside scripting and Mysql for the database server.Any help,codes are appreciated.

[JakeTheSnake3.0]

Since this is in the AJAX section of the forum - I'll answer your question with a Javascript solution...however this doesn't have much to do with AJAX itself....

 

Browsing the web for a simple window.open example, I came across this:

<script type="text/javascript">
function openwindow() {
    window.open("http://www.javascript-coder.com","mywindow","menubar=1,resizable=1,width=350,height=250");
}
</script>
<p>
<a href="javascript: openwindow()">Open the JavaScript Window Example 1</a>
</p>

 

All you have to do is take your current product variables, and create a name/pair string that will be appended to your url in the window.open method.

<?php

echo('<script type="text/javascript">
function openwindow(getProperties) {
    window.open("http://www.mydomain.com/?"+getProperties,"mywindow","menubar=1,resizable=1,width=350,height=250");
}
</script>
');

$stringAppend = "";
// let's say you had two variables...$prodName and $prodDescription....
$stringAppend .= "prodName=" .$prodName. "&prodDesc=" .$prodDescription;
// so now your $stringAppend looks like..."prodName=Chicken&prodDesc=this_is_chicken"....

echo('
<p>
<a href="javascript: openwindow(' .$stringAppend. ')">Open the JavaScript Window Example 1</a>
</p>
');

?>

 

So when you call your openwindow javascript function, your url will look like...http://www.mydomain.com/?prodName=Chicken&prodDesc=this_is_chicken

 

Hope this helps!

 

[rameshfaj]

That was only the window,but what i wanted is the popupwindow as you find in the many popular sites.Display the window in the same page.

I have posted a picture of the yahoo home page.Here the content section:Create one now- it's fast and easy!..is displayed on the popup window.

 

[attachment deleted by admin]

[JakeTheSnake3.0]

That is NOT a pop-up window...that's just a div that's been either created by javascript, or simply made visible by either javascript or css hover states.

[rameshfaj]

But what I wanted is the popup window for the same problem.

[JakeTheSnake3.0]

I have a database with entries like:itemid,itemname,itempicture,itemstock,...etc.

 

I have displayed the itemid,itempicture on the PHP pages.

Now what i want is that when the user clicks on the image of the item,the other informations about the item(selected from the database )should be displayed in the popup window.

 

I am using PHP for the serverside scripting and Mysql for the database server.Any help,codes are appreciated.

 

I don't see the relationship between your first post and the image you provided...the image you provided doesn't show anything related to 'additional information.

 

In your popup window, you can pass it GET variables that show the product ID...and in your php code you can just do an SQL query and supply the WHERE clause with the product id.