NEED HELP PLEASE: open directory of images but images won't display

[bensonang]

the code below displays all images located in the current directory.

my problem is, if i specify a directory name to $filedir, example $filedir = "pictures"; the only thing that would display

are blank boxes with an X (i think it means unloaded picture).

 

anyone had this kind of problem before? need suggestions please. thanks.

 

<?php

 

// Set $filedir to '.' if in current directory

$filedir = ".";

 

$handle = opendir($filedir);

echo $filedir;

while ($filename = readdir($handle)) {

 

    // One way to get the file extension

    $ext = strtolower(substr(strrchr($filename, '.'),1));

 

    if ($ext == 'jpeg' || $ext == 'jpg') {

        echo "<img src='$filename'>";

    }

}

closedir($handle);

 

?>

 

 

note: that pictures folder is located in the same directory as the php file.

 

 

[HaLo2FrEeEk]

Remember that you need to put the slashes in the path, otherwise you would get something like this for your url:

 

http://example.com/picturepicture1.jpg

 

when really you want this:

 

http://example.com/picture/picture1.jpg

 

Make sense?

 

Also, for browsing current directory, you should use ./, and not just .

 

So if the folder you wanted to browse was called pictures, use this for $filedir:

 

$filedir = './pictures/';

 

And finally, I didn't test your way of getting the extension, but this is the one I wrote:

 

$filetype = substr(strtolower($file), strrpos($file, ".")+1, strlen($file));

 

this gets everything in the now lowercase name called $file, after the last occurance of a dot in the filename, and up to the length of the file.

[bensonang]

Remember that you need to put the slashes in the path, otherwise you would get something like this for your url:

 

http://example.com/picturepicture1.jpg

 

when really you want this:

 

http://example.com/picture/picture1.jpg

 

Make sense?

 

Also, for browsing current directory, you should use ./, and not just .

 

So if the folder you wanted to browse was called pictures, use this for $filedir:

 

$filedir = './pictures/';

 

yep, however i tried it already and it still wont work. i'v tried using $filedir = "./pictures/"; $filedir="pictures/"; and i get the same results.

 

the output shows white boxes with corresponding size to the images in the pictures folder with a red x mark.

 

however, i noticed that if the pictures folder is empty, the screen would remain blank. does this mean the script really read the dir?

 

if i do use $filedir = "."; and put images in the same directory as the script, the output is correct (images displayed and all) im pretty confused right now.  ??? ???

 

[HaLo2FrEeEk]

I'm working on it, will edit, hopefully.

 

Try this:

 

<?php
$path = "./pictures/";
$handle = opendir($path);
while(($file = readdir($handle)) !== FALSE) {
  $ext = substr(strtolower($file), strrpos($file, ".")+1, strlen($file));
  $filename = substr($file, 0, strrpos($file, "."));
  $filename = str_replace(' ', '%20', $filename);
  if ($ext == 'jpeg' || $ext == 'jpg') {
    echo "<img src=" . $path . "" . $filename . "." . $ext . "><br />";
    }
  }
closedir($handle);
?>

 

The only problem I found was when there are spaces in the filename, for some reason, replacing them with %20 doesn't work, idk why, but other than that, as long as your foldername doesn't have a space, you'll be fine.