mmarif4u Posted March 5, 2007 Share Posted March 5, 2007 <?php $con = mysql_connect("localhost","root","adil"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("db", $con); $query = "SELECT * FROM accdtl where icnumber='123456-00-0012'"; $result = mysql_query($query) or die(mysql_error()); $ic=$row->icnumber; if ($ic == '123456-00-0012') { $disabled = "disabled"; } else{ $disabled = ""; } echo "<table class='text' align=Center CELLSPACING='0'BORDERCOLOR='#007FFF' BGCOLOR='cornsilk' border='1'> <tr><th colspan=12><Font face='Verdana'size='3'>Official Receipt</th></Font> <tr> <th><Font size='1'>Customer IC</th></Font> <th><Font size='1'>Acc Code</th></Font> <th><Font size='1'>Active</th></Font> <th><Font size='1'>Date</th></Font> </tr></tr>";while($row = mysql_fetch_array($result)) { echo "<tr>"; echo"<td>" . $row['icnumber'] . "</td></font>"; echo "<td>" . $row['acccode'] . "</td></font>"; echo "<td>" . $row['active'] . "</td></font>"; echo "<td>". $row['date'] . "</td></font>"; echo "</tr>"; } echo "</table>";mysql_close($con); echo ' <form> <input type="button" onClick="window.print()" value="Selection by Set" '.$disabled.' > </form> '; ?> This is the page where i want to disable the button but if the condotion is true. I try the php but not working, i am not good in javascript. How to use java for this to work. Any help will be appreciated. Thanks. Link to comment https://forums.phpfreaks.com/topic/41237-solved-help-in-button-disable/ Share on other sites More sharing options...
paul2463 Posted March 5, 2007 Share Posted March 5, 2007 I am not too sure on tis myself but here is what I think change the following if ($ic == '123456-00-0012') { $disabled = "disabled"; } else{ $disabled = ""; } to say if ($ic == '123456-00-0012') { $disabled = "True"; } else{ $disabled = "False"; } and change this line to read echo ' <form> <input type="button" onClick="window.print()" value="Selection by Set" disabled="'.$disabled.'" > </form> '; Link to comment https://forums.phpfreaks.com/topic/41237-solved-help-in-button-disable/#findComment-199836 Share on other sites More sharing options...
mmarif4u Posted March 6, 2007 Author Share Posted March 6, 2007 I try this changes its ok working, but the problem is now that the button is always disabled even i change the icnumber then also, this simple coding driving me crazy. I dont know where to correct it. Any suggestions. Thanks for reply. Link to comment https://forums.phpfreaks.com/topic/41237-solved-help-in-button-disable/#findComment-200484 Share on other sites More sharing options...
paul2463 Posted March 6, 2007 Share Posted March 6, 2007 try it this way then <?php if ($ic == '123456-00-0012') { $disabled = "disabled='true'"; } else{ $disabled = ""; } echo ' <form> <input type="button" onClick="window.print()" value="Selection by Set" $disabled > </form> '; Link to comment https://forums.phpfreaks.com/topic/41237-solved-help-in-button-disable/#findComment-200601 Share on other sites More sharing options...
mmarif4u Posted March 8, 2007 Author Share Posted March 8, 2007 Thanks Paul. I make some changes in the script and it works. Thanks for ur help. Link to comment https://forums.phpfreaks.com/topic/41237-solved-help-in-button-disable/#findComment-202252 Share on other sites More sharing options...
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