[SOLVED] log in problem

[reshpu]

this is my code:

 

<?php
session_start();

$con = mysql_connect("localhost","root");

if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("registo", $con);

$user = $_POST[user];
$senha = $_POST[password];

$login = mysql_query ("SELECT * FROM person WHERE login='$user' AND password='$senha'") or die(mysql_error());

//Contar numero de registos encontrados no mysql
$num_resultados = mysql_num_rows($login);

//Se ouver pelo menos 1 resultado, quer dizer q os dados estao correctos
if($num_resultados)
{
header("Location: paginaseguinte.php");
//Isto depois é para usar nas paginas seguintes, para nao se poder ir para essas paginas se n tiver feito o login
$_SESSION['autorizado']   = "Sim";
}

else
{
echo "Login Errado</br>";
echo "<a href=login.htm>Voltar ao login</a>";
}
?>

 

is simple but is always give error "login errado"

[iceman400]

well correct me if im wrong, but shouldnt  mysql_connect() also contain a password?

and is your using mysql > 4 all your code should be mysqli

[reshpu]

mysql_connet() dont have pass in my computer XD... so the program connect but never do the login....

[Kano]

HI there,

should you select statements where ....... = ('$_post[]'); ??

[Kano]

oops my mistake you created variables previously

[reshpu]

nop.... i do the same sh*** to the register.. and works now the login....

 

[iceman400]

i would echo $user and $senha to make sure they conatin values - when i leave out quote marks (') in array key names i sometimes get an error.

what u did:

$user = $_POST[user];
$senha = $_POST[password];

what i would try:

$user = $_POST['user'];
$senha = $_POST['password'];

[reshpu]

in beggin i have that

$user = $_POST['user'];

$senha = $_POST['password'];

 

i take off... is the same.... one big problem....

[reshpu]

the problem is:

 

my varibles dont work well.... so anyone can help me now.. i teste like this:

 

code:

<?php

session_start();

 

$con = mysql_connect("localhost","root");

 

if (!$con)

  {

  die('Could not connect: ' . mysql_error());

  }

 

mysql_select_db("registo", $con);

 

$user = $_POST[user];

$senha = $_POST[password];

echo $user;

 

 

ando dont print anything... plz help me  ???

[iceman400]

errm...can you post the code for the login form?

[reshpu]

ok now all the code

 

form code :

 

<form method="post" action="login.php" style="height: 231px">

<div class="style2">

 

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<strong>

<span class="style8">Utilizador: </span><span class="style6">           

 

<input name="User" type="text" class="style6" style="width: 129px; font-family: Arial; color: #000000;" />       

<input name="Button1" type="submit" value="Entrar" style="width: 58px; " class="style7" align="middle" /><br />

</span>

</strong><span class="style5"><strong><br />

</strong><span class="style3"><strong>Palavra Passe:  

</strong></span></span> <input name="Password" type="password" class="style6" style="width: 129px" />       

<input name="Button2" type="reset" value="Limpar" style="width: 58px; font-family: Arial; color: #FFFFFF; background-color: #000000;" class="style7" /><br />

<br />

 

<a href="registo.htm" class="style7">

<input name="Button3" type="button" value="Registar" style="font-family: Arial; color: #FFFFFF; background-image: url('iiiiiiiiiiiiiiiiiiiiiiii.JPG');" /></a></div>

</form>

 

 

 

ok.. plz help me out

[iceman400]

im not sure, but i think that once upon a time (im my dark days of using asp  ) i was making a form and put an "input" after the submit button and that messed everything up. try moving the submit button so its the very last element of the form. im not sure but i think that might work

[reshpu]

rsolve:

 

my problem is:

$user = $_POST['user'];

$senha = $_POST['password'];

 

resolve:

$user = $_POST['User'];

$senha = $_POST['Password'];

 

sry guys... ;D