[SOLVED] Why am I getting a parsing error?

[suttercain]

Simple submit form and I am getting a parsing error:

 

<?php
extract ($_REQUEST);
if (! isset ($submit_age) or $age =="") {
print "You Must Submit Your Age...<br />";
exit;
}

if ($age < 21) {
print "Sorry, youre too young to drink!";
}
else ($age >= 21)
print "Cool, youre $age! Lets get fu__ed up!!!";
}
?>

 

Thanks.

[per1os]

<?php
extract ($_REQUEST);
if (!isset($submit_age) || $age =="") {
print "You Must Submit Your Age...<br />";
exit;
}

if ($age < 21) {
print "Sorry, youre too young to drink!";
}
else ($age >= 21)
print "Cool, youre $age! Lets get fu__ed up!!!";
}
?>

 

or = ||

 

--FrosT

[suttercain]

Thanks frost, but I fixed that and it says error on line 20. Which is

print "Cool, youre $age! Lets get fu__ed up!!!";

[per1os]

else ($age >= 21) {
print "Cool, youre $age! Lets get fu__ed up!!!";
}

 

Need curly brackets at both ends.

 

--FrosT

[Barand]

 

 

 

FrosT,

 

regarding or / ||

 

read http://www.php.net/manual/en/language.operators.logical.php

[suttercain]

Did it, I saw that one, but now it says line 19....

 

All mixed up and I don't know what to do.

[suttercain]

Barand... so or is okay ansd so is and... right?

[per1os]

Did you do this?

 

<?php
extract ($_REQUEST);
if (!isset($submit_age) || $age =="") {
print "You Must Submit Your Age...<br />";
exit;
}

if ($age < 21) {
print "Sorry, youre too young to drink!";
}
else ($age >= 21) {
print "Cool, youre $age! Lets get fu__ed up!!!";
}
?>

 

Add the bracket on the else?

 

If so than please post the error that it gives you.

 

My bad barand, I forgot that php allows both. Thanks for correcting me.

 

--FrosT

[suttercain]

Here is the current code:

<?php
extract ($_REQUEST);
if (! isset ($submit_age) or $age =="") {
print "You Must Submit Your Age...<br />";
exit;
}

if ($age < 21) {
print "Sorry, youre too young to drink!";
}
else ($age >= 21) {
print "Cool, youre $age! Lets get fu__ed up!!!";
}
?>

Here is the error message:
Parse error: parse error, unexpected '{' in D:\wamp\www\PHP Tutorials\By Example\examples\chapter7_examples\lab_1a.php on line 19

[Barand]

Both work, but as it says in the manual, precedence is slightly different.

 

Whenever I use || I always put the conditions in parentheses to avoid precendence problems, paticularly when mixing && and ||

 

EG

 

if (!isset($submit_age) || ($age =="") )

[per1os]

<?php
extract ($_REQUEST);
if (! isset ($submit_age) or $age =="") {
print "You Must Submit Your Age...<br />";
exit;
}

if ($age < 21) {
print "Sorry, youre too young to drink!";
}
else {
print "Cool, youre $age! Lets get fu__ed up!!!";
}
?>

 

OR

 

<?php
extract ($_REQUEST);
if (! isset ($submit_age) or $age =="") {
print "You Must Submit Your Age...<br />";
exit;
}

if ($age < 21) {
print "Sorry, youre too young to drink!";
}
elseif ($age > 20 {
print "Cool, youre $age! Lets get fu__ed up!!!";
}
?>

 

The else either has to be an elseif for the condition or just an else without a condition

 

to Barand,

 

That is actually a really good idea. I am going to have to use it. Thanks for the insight (I have had problems with that in the past)

 

--FrosT

[suttercain]

BINGO... I can't believe I didn't catch that. None the less, thanks frost. elseif was the correction. Thanks.

[Barand]

@FrosT

 

It's particularly problematic when you have something like this

 

<?php
if (a == b && c == d || c == e)
?>

 

Do you really mean this  (default without the ()s )

 

<?php
if ( (a == b && c == d) || (c == e) )
?>

 

or do you mean this

 

<?php
if ( (a == b) && ( (c == d) || (c == e) ) )
?>