[SOLVED] correct syntax for if statement inside variable definition

[jswinkelman]

What is the correct syntax for the "if statement" below? I want to concatonate it with the information on either side. Without the information, the page shows Member_First Member_Last, as it should. With the "if statement," it shows a blank page. I know the syntax is incorrect. What should it be?

 

<?php $thisPage=($row_rs_Member['Member_First'].' '.<?php if ($row_rs_Member['Member_Middle'] <> NULL) echo $row_rs_Member['Member_Middle'].' '; ?>.$row_rs_Member['Member_Last']); ?>

 

Thanks!

[Orio]

You can't run php inside php (unless you are using eval()) and you can't use the regular if form inside a variable (although you can use the ternary operator)...

Do something like this:

 

<?php

$thisPage = $row_rs_Member['Member_First'].' ';
if ($row_rs_Member['Member_Middle'] <> NULL)
$thisPage .= $row_rs_Member['Member_Middle'].' ';
$thisPage .= $row_rs_Member['Member_Last'];

?>

 

 

Orio.

[per1os]

<?php

$thisPage = $row_rs_Member['Member_First'].' ';
if (!is_null($row_rs_Member['Member_Middle']))
$thisPage .= $row_rs_Member['Member_Middle'].' ';
$thisPage .= $row_rs_Member['Member_Last'];

?>

 

I believe if you are checking for null, the is_null() function php provides does wonders?

http://us3.php.net/manual/en/function.is-null.php

 

Also remember if you want to do more than 1 line of processing it should look like this:

 

<?php

$thisPage = $row_rs_Member['Member_First'].' ';
if (!is_null($row_rs_Member['Member_Middle'])) {
        // more than one line of processing here
$thisPage .= $row_rs_Member['Member_Middle'].' ';
}
$thisPage .= $row_rs_Member['Member_Last'];

?>

 

with the curly braces.

[jswinkelman]

I knew you'd know! Worked like a charm. Thanks for the tips!