Showing arrays, need help

[Jens14]

function date_diff($str_start, $str_end)

{

 

$str_start = strtotime($str_start);

$str_end = strtotime($str_end);

 

$nseconds = $str_end - $str_start;

$ndays = round($nseconds / 86400);

$nseconds = $nseconds % 86400;

$nhours = round($nseconds / 3600);

$nseconds = $nseconds % 3600;

$nminutes = round($nseconds / 60);

$nseconds = $nseconds % 60;

 

if ($ndays == 0)

if($nhours == 0)

if($nminutes == 0)

return array($nseconds);

else

return array($nminutes, $nseconds);

else

return array($nhours, $nminutes, $nseconds);

else

return array($ndays, $nhours, $nminutes, $nseconds);

 

}

 

date_diff("2007/03/16 12:30:50", "2007/03/16 14:00:00");

 

This is a function that compares two dates with each other and let's see how much there is left in seconds, minutes, hours, days.

 

I didn't know at all how to do the arrays but a friend gave me if else and return array stuff, the purpose is that first if for example the days and hours are 0 it only shows the minutes and seconds.

 

Can anyone tell me if I'm ussing the array's wrong or/and how i get the output from these?

 

Thanks, Jens.

[per1os]

function date_diff($str_start, $str_end)
{

$str_start = strtotime($str_start);
$str_end = strtotime($str_end);

$nseconds = $str_end - $str_start;
$ndays = round($nseconds / 86400);
$nseconds = $nseconds % 86400;
$nhours = round($nseconds / 3600);
$nseconds = $nseconds % 3600;
$nminutes = round($nseconds / 60);
$nseconds = $nseconds % 60;

if ($ndays == 0) 
if($nhours == 0)
if($nminutes == 0)
return array("seconds" => $nseconds);
else
return array("minutes" => $nminutes, "seconds" => $nseconds);
else
return array("hours" => $nhours, "minutes" => $nminutes, "seconds" => $nseconds);
else
return array("days" => $ndays, "hours" => $nhours, "minutes" => $nminutes, "seconds" => $nseconds);

}

$dateArr = date_diff("2007/03/16 12:30:50", "2007/03/16 14:00:00");

print_r($dateArr);

// to access array elements
print "Days" . $dateArr['days'] . " Hours:" . $dateArr['hours'] . " Minutes:" . $dateArr['minutes'] . " Seconds: " . $dateArr['seconds'];

 

If you have notices to set to display and the days or hours or minutes is not returned it will throw a notice because the index of 'days' is not defined in the array to avoid that notice do this for the function

 

function date_diff($str_start, $str_end)
{

$str_start = strtotime($str_start);
$str_end = strtotime($str_end);

$nseconds = $str_end - $str_start;
$ndays = round($nseconds / 86400);
$nseconds = $nseconds % 86400;
$nhours = round($nseconds / 3600);
$nseconds = $nseconds % 3600;
$nminutes = round($nseconds / 60);
$nseconds = $nseconds % 60;

// this will just return 0 for days if there are none., nothing wrong that.
return array("days" => $ndays, "hours" => $nhours, "minutes" => $nminutes, "seconds" => $nseconds);

}

$dateArr = date_diff("2007/03/16 12:30:50", "2007/03/16 14:00:00");

print_r($dateArr);

// to access array elements
print "Days" . $dateArr['days'] . " Hours:" . $dateArr['hours'] . " Minutes:" . $dateArr['minutes'] . " Seconds: " . $dateArr['seconds'];