preg_replace, +1 to matched number

[mzhou88]

preg_replace("/{$match}{$_Conf['FileManip']['Splitter']}(\d+)/i","{$match}{$_Conf['FileManip']['Splitter']}".$1+1,$Read)

 

Currently I am trying to figureout how to add 1  to the (\d+). but when i do whatever i did just now, it gives me  this error:

 

Parse error: syntax error, unexpected T_LNUMBER, expecting T_VARIABLE or '$' in D:\xampplite\htdocs\includes\bbcode.php on line 134

 

thx =p

[effigy]

I think the $1 has to be in quotes, which requires the /e modifier to do the addition:

 

<pre>
<?php
$string = '1';
echo preg_replace('/(\d+)/e', "$1+1", $string);
?>
</pre>