[SOLVED] Form data not being posted to receiving page

[doucie]

Hi All,

 

I've got the following function to get data and display in a selection list and then post to the receiving page but it does not seem to work.  Please help.

 

<?php

 

function get_groups()

{

  $db=mysqli_connect('localhost','root','','debtnet');

  if(mysqli_connect_errno())

  {

      echo 'Could not connect to the database';

      exit;

  }

  $query="SELECT cclientgroup FROM groups ORDER BY cclientgroup";

  $result=mysqli_query($db,$query); ?>

  <form action="group_report.php" method="POST" />

  <select name="Client" id="Client" />

  <?php while($list=mysqli_fetch_array($result)){

      echo "<option value='".$list['cclientgroup']."'>".$list['cclientgroup']."</option>";

  }

  echo "<input type='submit' value='Get Report'/>";

  echo "</form>";

}

 

?>

 

The code for the receiving page is this:

 

<?php $client = $_POST['cclientgroup']; ?>

<div id="box">

Information relating to client group: <?php echo $_POST['cclientgroup']; ?>

</div>

[freakstyle]

Hey Doucie,

 

this should do the trick for you:

 

<div id="box">

Information relating to client group: <?php echo $_POST['Client']; ?>

</div>

 

'you just needed to insert the name of the field you passed to the next page (instead of the actual value, the value is what is echo'd out above)

 

enjoy

[doucie]

Nice one.  Cheers