Create Listbox Depending On Variable

[MoFish]

hello everyone.

 

I currently have a variable called $NumPlayers which contains a number between 4 and 8;

 

depending on this value; i would like to create this amount of listboxes on my page. For example if the value of $NumPlayers is 6;

 

I would like 6 listboxes to be displayed on the page with names such as "Lstbox1" "Lstbox2".

 

I'm a bit clueless where to start; and was hoping someone could point me in the right direction.

 

Thanks alot, MoFish

[cx323]

untested, but it should be something like this:

 

<?php
for($i=1;$i<=$NumPlayers;++$i){
     echo '<select name="LstBox'.$i.'>
             <option value="">Choice</option>
             </select>';
}
?>

[MoFish]

seems to work a treat. thank you very much.

[MoFish]

it generates the right amount of boxes; but for some reason there is no values in the boxes. 

[cx323]

it looks like i forgot a quote.  it should be:

 

<?php
for($i=1;$i<=$NumPlayers;++$i){
    echo '<select name="LstBox'.$i.'">
            <option value="">Choice</option>
            </select>';
}
?>

[boo_lolly]

it looks like i forgot a quote.  it should be:

 

<?php
for($i=1;$i<=$NumPlayers;++$i){
    echo '<select name="LstBox'.$i.'">
            <option value="">Choice</option>
            </select>';
}
?>

 

 

your code is a little messed up. you want the select to be outside of the for loop. also there is even a little more missing as well... the value="" cannot be empty, otherwise it defeats the purpose of having a dropdown menu. no values will pass with the form from the dropdown menu. i'm not sure what value you'd put in there, but it needs to have one. my guess is you want it to look like this:

<?php
        echo "<select name=\"dropdown\">\n";
        for($i = 1; $i <= $NumPlayers; $i++){
                echo "<option value=\"{$i}\">{$i} player". (($i != 1) ? ('s') : ('')) ."\n";
        }
        echo "</select>\n";
?>

[MoFish]

hello again.

 

boo_lolly; i tested your code, and it puts the number of values into one listbox instead of generating the number of individual listboxes; cx323's code seemed to work in the correct mannor.

 

my next problem is populating these listboxes with data from a database. i want each listbox to be populated with the same list of data. I tryed the following code which worked well for the first listbox; but not the rest.

 

once these have been populated i hope to be able to select values from them; and submitted it in a form.

 

		$result = mysql_query("SELECT * FROM `tbl_players`");

			for($i=1;$i<=$NumPlayers;++$i){
    		
			echo '<select name="LstBox'.$i.'">';

			while ($myrow = mysql_fetch_array($result)) {
				$opt = $myrow['PlayerName'];
				echo "<option>$opt</option> ";
			}

			echo '</select>';
}

[cx323]

do you mean like this:

 

$result = mysql_query("SELECT * FROM `tbl_players`");
while ($myrow = mysql_fetch_array($result)) {
$opt .= '<option value="'.$myrow['PlayerName'].'">'.$myrow['PlayerName'].'</option>';
}
for($i=1;$i<=$NumPlayers;++$i){
echo '<select name="LstBox'.$i.'">'.$opt.'</select>';
}

[MoFish]

exactly like that!!! perfect!!!! thanks so much.

[MoFish]

sorry, didnt want to make a thread for something small like this ... why does the following formula not work?

 

$1stPlaceWinnings = $PlayerNumber * $BuyInPrice - $BuyInPrice;

 

Parse error: syntax error, unexpected T_LNUMBER, expecting T_VARIABLE or '$' in D:\wampnew\www\APL\ConfirmAndReport.php on line 91

 

the values are for example:

 

$PlayerNumber = 7

$BuyInPrice = 5

 

so - 7 * 5 = 35 then - 5 = 30

 

30 is the answer i need, but the above doesnt seem to work.

[Moon-Man.net]

$1stPlaceWinnings -- Remove the 1  from the start of your variable.

I donno, why, but that does it

-- Nathan

[cx323]

$1stPlaceWinnings -- Remove the 1  from the start of your variable.

I donno, why, but that does it

-- Nathan

 

it's because variable names must start with a letter or underscore