sw0o0sh Posted April 24, 2007 Share Posted April 24, 2007 I have an onclick that needs to repeat the function as many times as the user may decide to click. However, for some reason no matter what, if they click it once its only going to return the desired effect once, at which point they'd need to re open the page and click it again. Since I don't want to post the whole server side process, I have an example.. Here's "TCG.PHP", the page the AJAX communicates with. <?PHP echo rand(0,255); ?> Everytime they click a certain button, it calls the AJAX which calls that page. However, more than one click won't work. Say I push the button, it will return say (39?), and if i click again it just keeps 39 rather than redoing the server side process. And ofcourse, the AJAX function user(input){ var ajaxRequest; try{ ajaxRequest = new XMLHttpRequest(); } catch (e){ try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ alert("Your browser broke!"); return false; } } } ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState == 4){ var ajaxDisplay = document.getElementById('u1'); ajaxDisplay.innerHTML = ajaxRequest.responseText; } } var queryString = "?user=" + input; ajaxRequest.open("GET", "tcg.php" + queryString, true); ajaxRequest.send(null); } And also, the button in which they click: <input type='button' onclick='user("blabla")' /> Does anyone know what the issue is? >_> Quote Link to comment Share on other sites More sharing options...
sw0o0sh Posted April 24, 2007 Author Share Posted April 24, 2007 new note: works fine on FF, but not on IE7. I dont exactly want to shut out my IE7 users though.. so if anyone can help thatd be nice Quote Link to comment Share on other sites More sharing options...
xenophobia Posted April 27, 2007 Share Posted April 27, 2007 if(ajaxRequest.readyState == 4){ var ajaxDisplay = document.getElementById('u1'); ajaxDisplay.innerHTML = ajaxRequest.responseText; //need to close the connection. ajaxRequest = null; } Quote Link to comment Share on other sites More sharing options...
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