how to get variable name in function

[madrazel]

like this:

 

$f = "bang";

function listvars() {
$args = func_get_args();
foreach ($args as $val) {

echo $val."\n";

}; };

listvars($f,$f);

 

gives output:

 

bang
bang

 

how to make it display:

 

$f
$f

[monk.e.boy]

listvars('$f','$f');

 

hahah  ;D

 

whay would you want to?

 

Pass in the pointer to $f if you want to change it:

<?php

function xx( &$t )
{
$t++;
}

$t = 0;
xx( $t );

echo $t;

?>

 

See how this echos '1', the function xx has modified the variable $t because we passed a pointer to the function (the & means 'pointer to')

 

monk.e.boy

 

[madrazel]

actually i got something like this in mind:

 

$c = 'bang';
$f = 'c';

echo $$f."\n";

 

an now I'm struggling to make function with it, that will help me with debugging scripts

[monk.e.boy]

Have a look at var_dump.

 

But I can't see what finding out the name of the variable would do for you. Say we have a function called 'get_name' that would do what you want:

 

$a = 'boo';
echo get_name( $a ) .' = '. $a;

 

How is this better than just doing:

 

$a = 'boo';
echo '$a = '. $a;

 

? Eh?

 

Madness. For amazing debugging try getting NuSphere, PHPEd. It's brilliant.

 

monk.e.boy

 

 

[madrazel]

whatever, i done this:

 

function listvars($x) { $args = explode(',',$x); ob_start();
foreach ($args as $val) { global $$val;
echo '$'.$val.' = ';
if (is_null($$val)) { echo "NULL"; }
elseif ($$val === FALSE) { echo "FALSE"; }
elseif ($$val === TRUE) { echo "TRUE"; }
elseif ($$val === '') { echo "EMPTY"; }
elseif (is_array($$val)) { print_r($$val);}
else { echo $$val; };
echo "\n";  };
echo "<pre>\n".ob_get_clean()."</pre>\n";
};

$a="t";
$b='';
$c="h";

listvars("a,b,c");