Update a table using AJAX

[aniesh82]

 

Hello

 

I have a html form with action to paypal's site. When submitting the page, I need to update the table with the form values( USING AJAX) .

 

To do this I write the following code.

 

<script>

 

/* Call this function on the onClick of the submit button */

 

function check_form_values()

{

/* Inside this function I check wether the USER enters the details */

 

ajaxFunction();

 

/*  IT WORKS PERFECTLY IF WE UNCOMMENT THIS ALERT PAGE  */

}

 

 

function ajaxFunction()

{

 

append_url = 'contact_info.php?contact_id='+document.form1.user_id.value+'&contact_name='+document.form1.contact_name.value+'&position='+document.form1.position.value+'&email='+document.form1.email.value+'&telephone='+document.form1.telephone.value+'&mobile='+document.form1.mobile.value+'&company='+document.form1.company.value+'&address='+document.form1.address.value;

 

  var xmlHttp;

  try

    {

    // Firefox, Opera 8.0+, Safari

    xmlHttp=new XMLHttpRequest();

    }

  catch (e)

    {

    // Internet Explorer

    try

      {

      xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");

      }

    catch (e)

      {

      try

        {

        xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");

        }

      catch (e)

        {

        alert("Your browser does not support AJAX!");

        return false;

        }

      }

    }

    xmlHttp.onreadystatechange=function()

    {

      if(xmlHttp.readyState==4)

      {

//response_txt = xmlHttp.responseText;

 

  }

    }

    xmlHttp.open("GET",append_url,true);

    xmlHttp.send(null);

 

  }

 

</script>

 

I am trying to update the table using the contact_id field, I did not return any values from AJAX action page.

 

But this code did not work properly.

 

If I uncomment the alert inside the function "check_form_values()", then updation will work perfectly.

 

Can someone help me to fix this problem ?

 

 

Regards

Aniesh Joseph

 

 

[xenophobia]

What do you mean alert page? I don't see any alert() function there.  ???

[colandy]

I don't see that your doing anything at all with the AJAX returned responseText.

 

I also use AJAX as an object ....... var testObj = new AJAXFunction()

 

Here you appear to be using a function, creating the object inside the function and then doin not a lot with it, there's no check after the send only b4 so I'm assuming that it returns nothing. You don't use contact_id at all even though it's set at the beginning.

 

Just a few suggestions, hope they help

[Zaxnyd]

append_url = 'contact_info.php?

 

Might be irrelevant, but I noticed this line needs a closing, like so:

 

append_url = 'contact_info.php?';