[SOLVED] Putting in line breaks in a while loop?

[JJohnsenDK]

hey

 

im trying to run a while loop that puts in breaks (<br />) when 3 pictures have been displayed.

 

<?php
while($catListRow = mysql_fetch_array($searchQuery)){
echo "<p><a href='gallery.php?action=3&no=".$catListRow['download_id']."&cat=".$catListRow['download_cat']."'><img src='".$catListRow['download_url']."' height='100' alt='".$catListRow['download_title']."' /></a></p>";
}
?>

 

as the code are at the moment it just prints out all the pictures in one long line. How do i get the script to put in a line break everytime 3 pictures have been printed?

[papaface]

<?php
$_num = 0
while($catListRow = mysql_fetch_array($searchQuery))
{
echo "<p><a href='gallery.php?action=3&no=".$catListRow['download_id']."&cat=".$catListRow['download_cat']."'><img src='".$catListRow['download_url']."' height='100' alt='".$catListRow['download_title']."' /></a></p>";
$_num++;
if ($_num == 3)
{
echo "<br>";
}
}
?>

Untested

[JJohnsenDK]

that wont work because there can be 13 or 100 pictures so that script you posted will only put in line breaks after the 3 first pictures..

 

any ohter suggentions?

[snowdog]

Only one thing I would add. If you want to display more than 6 pictures and need more breaks then you need to reset the counter to 0 when you add the break.

 

<?php

$_num = 0

while($catListRow = mysql_fetch_array($searchQuery))

{

echo "<p><a href='gallery.php?action=3&no=".$catListRow['download_id']."&cat=".$catListRow['download_cat']."'><img src='".$catListRow['download_url']."' height='100' alt='".$catListRow['download_title']."' /></a></p>";

$_num++;

if ($_num == 3)

{

echo "<br>";

$_num = 0;

}

}

?>

 

 

Snowdog

[papaface]

^^^ Good point, forgot about that.

[JJohnsenDK]

Ahh yes ofcause... thanks for helping out