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H, i have a simple database i wish to UPDATE via a form using php 5 / mysql 5.

 

The way i call the item to edit is via: /manageedit.php?id=3 (example <a href=http://agtrac.com.au/test1/manageedit.php?id=3>here</a>) this should display the current values from the database but is not showing anything and upon submit returns:

 

ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'special2 = '' WHERE id =' at line 1 UPDATE products SET title = '', description = '', retail = '', special = '' special2 = '' WHERE id =

 

I need the valued service of an expert to point out to me what the missing link is. I have spent days going around in circles trying various methods from database tutorials, with no success.

 

If someone can assist i would be very greatful, hope i have included enough info. The current source code is below:

 

<a href=http://agtrac.com.au/test1/manageedit.php?id=3>manageedit.php</a>

<?php
    $usr = "user";
    $pwd = "pass";
    $db = "dbname";
    $host = "localhost";

    #connect to database
    $cid = mysql_connect($host,$usr,$pwd);
    if (!$cid) { echo("ERROR: " . mysql_error() . "\n");    }
?>
<HTML>
<HEAD>
   <TITLE>Update Link</TITLE>

</HEAD>
<BODY BGCOLOR="#FFFFFF">
<TABLE WIDTH="100%">
<TR><TD><FONT SIZE=5><B> Update Link </B> </FONT></TD>
     <TD VALIGN=TOP ALIGN=RIGHT><FONT SIZE="-1"><A HREF="javascript: self.close()">Close Window</A></FONT></TD>
</TR></TABLE>
<?

    # processed when form is submitted back onto itself
    if (isset($_POST['submit'])) {

        # setup SQL statement
        $SQL = " UPDATE products SET";
        $SQL = $SQL . " title = '$title', ";
        $SQL = $SQL . " description = '$description', ";
        $SQL = $SQL . " retail = '$retail', ";
        $SQL = $SQL . " special = '$special' ";
$SQL = $SQL . " special2 = '$special2' ";
        $SQL = $SQL . " WHERE id = $id ";

        # execute SQL statement
        $result = mysql_db_query($db,"$SQL",$cid);

        # check for errors
        if (!$result) { echo("ERROR: " . mysql_error() . "\n$SQL\n");    }

        echo ("<P><B> Link Updated</B></P>\n");

    }
    else { # display edit form (not post method)

        # setup SQL statement to retrieve link
        # that we want to edit
        $SQL = " SELECT * FROM products ";
        $SQL = $SQL . " WHERE id = $id ";

        # execute SQL statement
$ret = mysql_select_db($db,$SQL,$cid);

        # retrieve values
        $row = mysql_fetch_array($ret);
        $title = $row["title"];
        $description = $row["description"];
        $retail = $row["retail"];
        $special = $row["special"];
$special2 = $row["special2"];

?>

<FORM NAME="fa" ACTION="manageedit.php" METHOD="POST">
<INPUT TYPE="hidden" NAME="id" VALUE="<?php echo("$id"); ?>">
<TABLE>
<TR><TD><B>Title: </B> </TD><TD><INPUT TYPE="text" NAME="category" VALUE="<?php echo("$title"); ?>" SIZE=70></TD></TR>
<TR><TD><B>Description:</B> </TD><TD><TEXTAREA NAME="description" ROWS=5 COLS=40><?php echo("$description"); ?></TEXTAREA></TD></TR>
<TR><TD><B>Retail: </B> </TD><TD><INPUT TYPE="text" NAME="siteurl" VALUE="<?php echo("$retail"); ?>" SIZE=40></TD></TR>
<TR><TD><B>Special: </B> </TD><TD><INPUT TYPE="text" NAME="siteurl" VALUE="<?php echo("$special"); ?>" SIZE=40></TD></TR>
<TR><TD><B>Special2: </B> </TD><TD><INPUT TYPE="text" NAME="siteurl" VALUE="<?php echo("$special2"); ?>" SIZE=40></TD></TR>
<TR><TH COLSPAN=2><P><INPUT TYPE="submit" name="submit" VALUE="Update Link"></P></TH></TR>
</TABLE>
</FORM>


<?php    }

mysql_close($cid);

?>
</BODY>
</HTML>

Link to comment
https://forums.phpfreaks.com/topic/49405-solved-unable-to-update-from-php-script/
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You may need to select a database before performing any queries.

the database ($db) is "dbname" and the table is "products", executed as mysql_db_query($db,"$SQL",$cid);

 

i also tried mysql_select_db($db, $cid); but sadly that didn't help. i'm still lost.  :-\ really hope i get some progress, ive been days now on this issue.

 

oh - ok... Clicking the [update Link] button on the link provided produced the following page

ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'special2 = '' WHERE id =' at line 1 UPDATE products SET title = '', description = '', retail = '', special = '' special2 = '' WHERE id = 

 

$id does not appear to be set anywhere.

 

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