rebeat Posted May 1, 2007 Share Posted May 1, 2007 H, i have a simple database i wish to UPDATE via a form using php 5 / mysql 5. The way i call the item to edit is via: /manageedit.php?id=3 (example <a href=http://agtrac.com.au/test1/manageedit.php?id=3>here</a>) this should display the current values from the database but is not showing anything and upon submit returns: ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'special2 = '' WHERE id =' at line 1 UPDATE products SET title = '', description = '', retail = '', special = '' special2 = '' WHERE id = I need the valued service of an expert to point out to me what the missing link is. I have spent days going around in circles trying various methods from database tutorials, with no success. If someone can assist i would be very greatful, hope i have included enough info. The current source code is below: <a href=http://agtrac.com.au/test1/manageedit.php?id=3>manageedit.php</a> <?php $usr = "user"; $pwd = "pass"; $db = "dbname"; $host = "localhost"; #connect to database $cid = mysql_connect($host,$usr,$pwd); if (!$cid) { echo("ERROR: " . mysql_error() . "\n"); } ?> <HTML> <HEAD> <TITLE>Update Link</TITLE> </HEAD> <BODY BGCOLOR="#FFFFFF"> <TABLE WIDTH="100%"> <TR><TD><FONT SIZE=5><B> Update Link </B> </FONT></TD> <TD VALIGN=TOP ALIGN=RIGHT><FONT SIZE="-1"><A HREF="javascript: self.close()">Close Window</A></FONT></TD> </TR></TABLE> <? # processed when form is submitted back onto itself if (isset($_POST['submit'])) { # setup SQL statement $SQL = " UPDATE products SET"; $SQL = $SQL . " title = '$title', "; $SQL = $SQL . " description = '$description', "; $SQL = $SQL . " retail = '$retail', "; $SQL = $SQL . " special = '$special' "; $SQL = $SQL . " special2 = '$special2' "; $SQL = $SQL . " WHERE id = $id "; # execute SQL statement $result = mysql_db_query($db,"$SQL",$cid); # check for errors if (!$result) { echo("ERROR: " . mysql_error() . "\n$SQL\n"); } echo ("<P><B> Link Updated</B></P>\n"); } else { # display edit form (not post method) # setup SQL statement to retrieve link # that we want to edit $SQL = " SELECT * FROM products "; $SQL = $SQL . " WHERE id = $id "; # execute SQL statement $ret = mysql_select_db($db,$SQL,$cid); # retrieve values $row = mysql_fetch_array($ret); $title = $row["title"]; $description = $row["description"]; $retail = $row["retail"]; $special = $row["special"]; $special2 = $row["special2"]; ?> <FORM NAME="fa" ACTION="manageedit.php" METHOD="POST"> <INPUT TYPE="hidden" NAME="id" VALUE="<?php echo("$id"); ?>"> <TABLE> <TR><TD><B>Title: </B> </TD><TD><INPUT TYPE="text" NAME="category" VALUE="<?php echo("$title"); ?>" SIZE=70></TD></TR> <TR><TD><B>Description:</B> </TD><TD><TEXTAREA NAME="description" ROWS=5 COLS=40><?php echo("$description"); ?></TEXTAREA></TD></TR> <TR><TD><B>Retail: </B> </TD><TD><INPUT TYPE="text" NAME="siteurl" VALUE="<?php echo("$retail"); ?>" SIZE=40></TD></TR> <TR><TD><B>Special: </B> </TD><TD><INPUT TYPE="text" NAME="siteurl" VALUE="<?php echo("$special"); ?>" SIZE=40></TD></TR> <TR><TD><B>Special2: </B> </TD><TD><INPUT TYPE="text" NAME="siteurl" VALUE="<?php echo("$special2"); ?>" SIZE=40></TD></TR> <TR><TH COLSPAN=2><P><INPUT TYPE="submit" name="submit" VALUE="Update Link"></P></TH></TR> </TABLE> </FORM> <?php } mysql_close($cid); ?> </BODY> </HTML> Quote Link to comment Share on other sites More sharing options...
bubblegum.anarchy Posted May 1, 2007 Share Posted May 1, 2007 You may need to select a database before performing any queries. Quote Link to comment Share on other sites More sharing options...
rebeat Posted May 1, 2007 Author Share Posted May 1, 2007 You may need to select a database before performing any queries. the database ($db) is "dbname" and the table is "products", executed as mysql_db_query($db,"$SQL",$cid); i also tried mysql_select_db($db, $cid); but sadly that didn't help. i'm still lost. :-\ really hope i get some progress, ive been days now on this issue. Quote Link to comment Share on other sites More sharing options...
bubblegum.anarchy Posted May 1, 2007 Share Posted May 1, 2007 oh - ok... Clicking the [update Link] button on the link provided produced the following page ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'special2 = '' WHERE id =' at line 1 UPDATE products SET title = '', description = '', retail = '', special = '' special2 = '' WHERE id = $id does not appear to be set anywhere. Quote Link to comment Share on other sites More sharing options...
rebeat Posted May 1, 2007 Author Share Posted May 1, 2007 I used $id=$_POST['id'] which found the id, i still have problems tho but i need to move on as it is a time sensitive issue. cheers. Quote Link to comment Share on other sites More sharing options...
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