[SOLVED] if statement for database

[kidintraffic]

I have a form that a user can enter data and upload an image that is stored in a database.  The user doesn't have to upload an image but has to enter data into the rest of the form.  When pulling the information from the database I was wondering how you would say

 

if the database name for the image is empty then display a default image.  and if there is data in the database for the image name then display the image specified.

 

 

I know to display the image that is in the database I use this code

<img src="uploads/<? echo $imgname; ?>" />

 

[triphis]

$imgname (pulled from that cell in the DB table)

 

if($imgname == NULL) // or whatever you set as default
{ echo "<img src='default.gif'>" /> }
else
{ echo "<img src='uploads/<?=$imgname?>' />" }

   

 

edit:

 

When the form is submitted, you can check to see if they are uploading something or not, and then set the DB cell to whatever you decide Then check based on that.

[kidintraffic]

When the form is submitted, you can check to see if they are uploading something or not, and then set the DB cell to whatever you decide Then check based on that.

 

How would I do that?