N00b Parse error help

[Swerve1000]

Hi,

 

I'm following a tutorial and am having trouble with one line of my code:-

 

 

    <td>year_promoted</td>

    <td>promotor</td>

    <td>students</td>

  </tr>

  <?php do ( ?>    <--------------ERROR ON THIS LINE (line 42)

  <tr>

    <td><?php echo  $row['id']; ?> </td>

    <td><?php echo  $row['first_name'];  ?></td>

    <td><?php echo  $row['last_name'];  ?></td>

    <td><?php echo  $row['nickname'];  ?></td>

    <td><?php echo  $row['belt'];  ?></td>

    <td><?php echo  $row['belt_rank'];  ?></td>

    <td><?php echo  $row['country'];  ?></td>

    <td><?php echo  $row['year_promoted'];  ?></td>

    <td><?php echo  $row['promotor']; ?></td>

    <td><?php echo  $row['students']; ?></td>

  </tr>

  <?php  )while ($row = mysql_fetch_array($result)); ?>

</table>

</body>

</html>

 

---------------------------------------------------------------------------

 

The error I get is:-

 

Parse error: syntax error, unexpected ';' in C:\wamp\www\results.php on line 42

 

This is how the guy has the code in the tutorial and it works for him, but is failing to run for me.

 

It's use to to keep creating rows in a table until all results are displayed on that table.

 

I'm stuck

 

 

[pocobueno1388]

Try changing this line:

<?php do ( ?>

 

to:

<?php do { ?>

 

I have no idea why you are using the "do" though....

 

EDIT:

Oh, and change this line:

<?php  )while ($row = mysql_fetch_array($result)); ?>

 

to

 

<?php  } while ($row = mysql_fetch_array($result)); ?>

[Swerve1000]

Thank you sir.!

 

Fixed!!

 

As for the 'Do',

 

I do not know, the tutorials saying were using it to keep displaying result rows until none are left in the variable $row which contains all the data.

 

 

 

 

[MadTechie]

please click solved!