Displaying gender photo

[graham23s]

Hi Guys,

 

i have a script here that echoes out a users photo (if they have uploaded one) if not it's just a generic one, what i was wanting to do is display a generic male one if they are male and a female pic if they are female, the code just now is:

 

<?php     
     // Start retrieving user profile from database//////////////////////////////////////
    $qProfile = "SELECT * FROM membership WHERE username='$member'";
    $rsProfile = mysql_query($qProfile) or die(mysql_error());

    $row = mysql_fetch_array($rsProfile); // get the resultset into an array/////////////
    extract($row);
    
    // The row items in variables.../////////////////////////////////////////////////////
    $id = $row['id'];
    $photo1 = $row['photo1'];
    $gender = $row['gender'];
?>
<p>Upload Main Profile Photo<p>
<table width="600" cellspacing="2" cellpadding="2">
<form action="upload_photo_done.php" method="POST" enctype="multipart/form-data">
<tr>
<td bgcolor="#E2E2E2">Upload Location:</td><td bgcolor="#E2E2E2" align="left"><input type="file" name="image1" size="40"></></td>
<tr>
<td bgcolor="#E2E2E2">Current Uploaded Photo:</td><td bgcolor="#E2E2E2">
    <?php     
    if($photo1 == 0) {         
     echo "<img src='uploads/no_pic_male.jpg' />";           
       } else {            
     echo "<img src='uploads/$photo1' border='0' />"; 
}
?>

 

i was thinking an elseif statement is that possible?

 

cheers

 

Graham

[only one]

yes an else if is possilbe

 

if(something==theotherthing){ do something

}else if(something==somethingelse){ do something else

}else{ do the other ting... }

[nikkieijpen]

If they didn't upload a photo the the value stored in the database field 'photo1' really is 0 or is it empty?

 

if it's empty:

<?php     
    if(empty($photo1)) {         
      switch ($gender) {
              case "male": echo "<img src='uploads/no_pic_male.jpg' />"; break;
              case "female": echo "<img src='uploads/no_pic_female.jpg' />"; break; 
              default: echo "<img src='uploads/no_pic.jpg' />"; break; 
       } else {            
     echo "<img src='uploads/$photo1' border='0' />"; 
}
?>

 

If it's 0 just leave the if statement as you already had it.

[btherl]

As an aside, there is no need to extract($row) if you are going to explicitly set $id, $photo1 and $gender below.  They both perform the same action (though the extract will set all variables, not just the ones you want).

[graham23s]

Hi Guys,

 

Thanks for the help the $photo1 field was indeed empty.

 

i have implemented this code by Nikki

 

<?php     
    if(empty($photo1)) { 
            
      switch ($gender) {
      
              case "Male": echo "<img src='images/no_pic_male.jpg' />"; 
              break;
              
              case "Female": echo "<img src='images/no_pic_female.jpg' />";
              break;     
       }
              
       } else {  
                 
              echo "<img src='uploads/$photo1' border='0' />"; 
}
?>   

 

this does the job it echoes out a female or a male picture depending on signup, only thing is, when i upload a photo in the control panel, it doesn't store the name in mysql (even though it says uploaded succesfully) but if i revert to my initial basic code:

 

    <?php     
    if($photo1 == 0) {         
     echo "<img src='uploads/no_pic_male.jpg' />";           
       } else {            
     echo "<img src='uploads/$photo1' border='0' />"; 
}
?>

 

it seems to work as before, storing the name in mysql any ideas on why it didn't do this with the revised code?

 

thanks guys

 

Graham