Sessions problem

[Suchy]

I hava a session variable that holds an int passed from a previous page, the new page looks like:

session_start();
session_register ("new_id");
$id = $_GET['id']; // passed from previous page
$_SESSION['new_id'] = $id;

 

Then on this page I have a submit form

if(in("submit")) {
...
session_start(); 
$_SESSION['new_id'] = $temp ; 
$query = "SELECT * FROM names WHERE id = '$new_id' ";
...

 

When I press the submit button the session inside the if(in("submit")) function is not working?

 

What is wrong with my code, and how to fix it?

[btherl]

What is in() ?  It is not part of standard php.

[Suchy]

When I press the submit button on the form that function kicks in to insert values into MYSQL

[btherl]

Can you post the rest of your script?

 

I don't understand your description of what your code is supposed to do either.

 

And please describe in detail what "the if(in("submit")) function is not working" looks like.  What do you see on the screen?  What did you expect to see?

[Suchy]

I use this function anytime I have a form, since I can have multiple forms with multiple id (ex. id="submit" , then a second form id="update" then third id="delete"...)

and then I can have multiple functions ex:

if(in("update"))
{    
 $id = $_POST['id'];
 $contacted = $_POST['contacted'];
 $done = $_POST['done'];
 $paid = $_POST['paid'];
 $jobnotes = mysql_real_escape_string($_POST['jobnotes']);

 $query = "UPDATE entries SET contacted = '$contacted' , done = '$done' , paid = '$paid' , jobnotes = '$jobnotes' WHERE id = '$id' ";

 $result = mysql_query($query);
} 

///

if(in("Delete"))
{  
 $id = $_POST['id'];
 $query = "DELETE FROM entries WHERE id = '$id'";
 $result = mysql_query($query);
} 

 

These are just examples from previous sites.

 

 

 

The function that I am talking about is:

if(in("submit"))
{    

 session_start(); 
 $_SESSION['new_id'] = $xxx ; 

$query = "SELECT * FROM photo WHERE id = '$new_id' ";
$result = mysql_query($query);
$entriesResults = getRows($result);
}

 

No what I suposed to ge is the picture that has that id.

 

and then use the $new_id in <img src=" "> tag

 

 

 

[btherl]

If you want to get $new_id from the session, you should do this:

 

$new_id = $_SESSION['new_id'];

[Suchy]

This is not working.

 

Also in the code I posted above it should be:

$query = "SELECT * FROM photo WHERE id = '$xxx' ";

 

and not

 

$query = "SELECT * FROM photo WHERE id = '$new_id' ";