PHP: function help

[Ben Phelps]

function newFunction($var1, $var2, $optVar1, $optVar2)
{
    echo $var1;
    echo $var2;
    if (isset($optVar1)) {
        echo $optVar1;
    }
    if (isset($optVar2)) {
        echo $optVar2;
    }
}

 

I get:

Warning: Missing argument 3 for newFunction()

Warning: Missing argument 4 for newFunction()

and i understand why, but how can I have those optional variables and not get that error.

[pocobueno1388]

By setting them to a default value like this:

 

<?php

function newFunction($var1=NULL, $var2=NULL, $optVar1=NULL, $optVar2=NULL)
{
    echo $var1;
    echo $var2;
    if (isset($optVar1)) {
        echo $optVar1;
    }
    if (isset($optVar2)) {
        echo $optVar1;
    }
}

?>

[per1os]

<?php
function newFunction($var1, $var2, $optVar1=NULL, $optVar2=NULL)
{
   echo $var1;
   echo $var2;
   if (!is_null($optVar1)) {
       echo $optVar1;
   }
   if (!is_null($optVar2)) {
       echo $optVar1;
   }
}

[Ben Phelps]

Thanks for the fast answers, they both helped.