adzie Posted May 28, 2007 Share Posted May 28, 2007 Hi peeps, I want to insert an image based on a value in a DB The script I have so far is, the problem is every record is assigned red three as an image? any thoughts or suggestions? $red = ($red); if ($red = '0') { ?> <img src="./one.gif"> - red zero <?php }else if ($red = '3') { ?> <img src="./two.gif"> - red three <?php }else if ($red = '2') { ?> <img src="./three.gif"> - red two <?php }else if ($red = '1') { ?> <img src="./four.gif"> - red one <?php } ?> Quote Link to comment https://forums.phpfreaks.com/topic/53269-solved-image-from-variable/ Share on other sites More sharing options...
MadTechie Posted May 28, 2007 Share Posted May 28, 2007 try this <?php $red = ($red); switch($red) { case '0': echo '<img src="./one.gif"> - red zero'."($red)"; break; case '1': echo '<img src="./four.gif"> - red one'."($red)"; break; case '2': echo '<img src="./three.gif"> - red zero'."($red)"; break; } ?> Quote Link to comment https://forums.phpfreaks.com/topic/53269-solved-image-from-variable/#findComment-263215 Share on other sites More sharing options...
adzie Posted May 28, 2007 Author Share Posted May 28, 2007 spot on mad techie, thankyou for the help topic solved Quote Link to comment https://forums.phpfreaks.com/topic/53269-solved-image-from-variable/#findComment-263216 Share on other sites More sharing options...
MadTechie Posted May 28, 2007 Share Posted May 28, 2007 note you can remove the ."($red)" as they are just for debugging Quote Link to comment https://forums.phpfreaks.com/topic/53269-solved-image-from-variable/#findComment-263218 Share on other sites More sharing options...
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