[SOLVED] another regex prob

[sniped22]

$usernam = substr($pokerhand, 9, $pos2-9);

$username ="<font color='blue'>$usernam:</font>";

//$text_out definately contains $usernam.


preg_replace($usernam, $username, $text_out);

 

how do I use variables as patterns and replacements?

 

Thanks

[Wildbug]

You need to use delimiters, and I would also suggest using preg_quote with your delimiter of choice to make sure everything in the pattern is recognized as a literal.  Every pattern must be contained within delimiters.  (/this is a pattern/)

[sniped22]

$text_out = preg_replace('/$usernam/', $username, $text_out); // doesnt work
$text_out = preg_replace('/\$usernam/', $username, $text_out); // doesnt work
$text_out = preg_replace('/$usernam/', '/$username/', $text_out); // doesnt work
$text_out = preg_replace($usernam, $username, $text_out); // doesnt work

//can't figure it out!!!!

 

i know that you know the answer and were trying to lead me in the correct direction, but i think if you

show me how you would do it, i would know how to use it from here on.

 

Thanks again

[sniped22]

preg_replace("/$usernam/", $username, $text_out);

 

WORKS!!!

[Wildbug]

Right, you needed the double quotes to interpolate the variable.  Also, unless there will never be metacharacters in $usernam (chars. like /[*., etc; anything with special meaning in a regex), you should use preg_quote to make sure they are escaped.

 

preg_replace('/' . preg_quote($usernam,'/') . '/', $username, $text_out);