[SOLVED] Finding the mode

[pea_1]

Can't figure out how to find the mode of a file (string occurring most often). Has anyone else managed to do it?

 

Peter

[Lumio]

If you mean fileperms:

www.php.net/fileperms

www.php.net/is_readable

www.php.net/is_writeable

[pea_1]

no the mathematical mode. the mode is the most often value.

 

For example, for 1,2,2,2,3

 

2 would be the mode

[Orio]

I really don't understand what you are looking for...

Are you sure it's not fileperms() you need?

 

Orio.

[pea_1]

Umm.. this is *extremely* simple maths. Maybe this will help you http://www.manatee.k12.fl.us/sites/elementary/palmasola/mathlabtutstat1.htm

[Orio]

Oh ok lol

I assume the numbers are in an array?

 

<?php
//The numbers are in an array called $array

$count = array_count_values($array);
sort($count);

echo $count[0];

?>

 

 

Orio.

[pea_1]

The array doesn't contain numbers though, they're words

[taith]

made this just now...

 

<?php
function mode($array){
foreach($array as $k=>$v){
  $mode[trim($v)]++;
}
foreach($mode as $k=>$v){
  if($v>$highest[num]){
   $highest[num]=$v;
   $highest[word]=$k;
  }
}
return $highest[word];
}

$string='word, test, word, test2, word';
$array=explode(',',$string);
echo mode($array);
?>

[pea_1]

Ah thanks, i was completely lost on this one, but this seems to do the trick.

[Orio]

Btw, the code I supplied works with words too, it just needs a little change (although it might work this way too).

 

Orio.

[pea_1]

Yeh it does. I also managed to get the top 5:

 

$excludes = array();

$i = 1;
while($i <= 5){
$i++;

$output = mode($array);

foreach($array as $lnum => $line){
array_push($excludes, trim($output));
foreach($excludes as $exclude){

if(trim($line) == $exclude){
unset($array[$lnum]);

}
}
}
echo "$output<br>";

[Lumio]

Please click on topic solved