[SOLVED] PHP String Functions

[rastrol7]

I'm trying to find the correct function or use of the str_replace() function to substitute every space (' ') in my code with an ampersand.

 

I've tried doing:

str_replace(' ', '&', $input)

and several variations to no success. Is there an easy way to do this that I've just missed?

 

Thanks!

[per1os]

www.php.net/str_replace

 

 

<?php
$input = str_replace(' ', '&', $input);
?>

 

Have you tried it like that if that does not work try this:

 

<?php
$input = str_replace(' ', '\&', $input); // maybe the amersand needs escaped?
?>

[rastrol7]

Nope I've tried all the tricks I could on the ampersand. I think the problem is in reading ' ' as a space. The function works for any other character in the string.

[Caesar]

Where are you pulling your input from? Is it formatted in any way? str_replace() should work fine the way frost showed.

[rastrol7]

I'm trying to convert a series of characters in a string into an array. The starting string is:

Medium=+0 Large=+0 X-Large=+0 2XB=+1 3XB=+1 4XB=+1 5XB=+2 6XB=+2 7XB=+3 8XB=+3 9/10XB=+4 11/12XB=+8 LT=+1 1XLT=+1 2XLT=+1 3XLT=+1 4XLT=+1 5XLT=+2 6XLT=+2 7/8XLT=+3 9/10XLT=+6

 

I want to end up with an array that associates each size with the number after the "=+".

 

I know that the following will convert my string into an array where [Medium] => +0, [Large] => 0, etc...

<?php
parse_str($string, $array);
?>

but only if I can have an '&' where each space is.

 

So in short, any ideas on how to add that & or a better way to do this?

[rastrol7]

Turns out the output from the mysql query wasn't

 
Medium=0 Large=0 X-Large=0 2XB=+1 ... 

it was actually

Medium=0\r\nLarge=0\r\nX-Large=0\r\n2XB=+1 ... 

 

the \r\n never showed up as I was developing the site, but once I put in

<?php
$out = str_replace("\r\n",'&', $out);
?>

everything worked fine.

 

Thanks anyway for the help!