[SOLVED] in_array ?

[MemphiS]

I keep getting the following error:

 

Warning: in_array() [function.in-array]: Wrong datatype for second argument in

 

Code example:

$post1 = $_POST['number1'];
$post2 = $_POST['number2'];
$post3 = $_POST['number3'];

$array1 = array("1","2","3");
$array2 = array("$post1","$post2","$post3");
$array3 = array("1","2","3","$post1","$post2","$post3");

if (in_array("1", $array2)){ print("1 has been found."); }
if (in_array("1", $array3)>2){ print("1 has been found twice in array 3."); }

 

Once the POST values have been set its fine... and when not set they have no value and dispplays the above error... is there a solution to overcome this problem?

[chigley]

Whats )>2 for when declaring the array haystack in the second if statement?

[MemphiS]

For if the number "2" is in the array more then once

[MemphiS]

The problem is that none of the array values in $post1 etc have been set so the array would look like $array2 = array("","","",""); untill i submit my $_POST data... not to sure how to fix this problem

[MemphiS]

hehe Nevermind i thought up a solution