preg_match

[Baving]

Hello,

 

I am currently using a script which retrieves the following information "1,600 users online", however I only want the number.

 

So is there anyway using preg_match to only get like "1,600"?

 

Thanks

[pocobueno1388]

Just use your query:

 

<?php

$sql = mysql_query("SELECT count(*) FROM users WHERE last_online > TIME");
$num = mysql_num_rows($sql);

echo 'There are '.$num.' users online';

?>

 

Obviously your gonna have to change the query to match your needs.

[Baving]

I am not getting it from a database, I am getting the file contents from another site and then exploding the div tag to retrieve the content.

 

Code: -

if(@$_GET['do']=='getcount') {
$ext = @$_GET['ext'];

$file = file_get_contents("http://sitehere".$ext);

$explode = explode("<td id=\"topbar-count\">",$file,2);
$explode2 = explode("</td>", $explode[1],2);
$count = $explode2[0];
echo $count;
}

 

I need the preg_match somewhere in there to remove the members online and only show the number.

[pocobueno1388]

Oh, I'm sorry...I read the question wrong.

 

Well...I am assuming the number of people online will always be at the beginning of the string, right?

 

So you can just use an explode on it and it should be the first value stored in your array all the time.

[jaikar]

 

$count = '1,600 users online';

$count = str_replace($count, '', 'users online');

 

if not works..

 

$count = str_replace($count, '', 'users');

$count = str_replace($count, '', 'online');

[MadTechie]

using preg_match

try

$data = "1,600 users online";
if (preg_match('/^(.[0-9,.]+)/', $data, $regs)) {
$result = $regs[0]; //1,600
} else {
$result = ""; // not found
}