[SOLVED] Need guidence with dropdown menu and arrays

[jim.davidson]

I'm using php dreamweaver 8 and mySQL 4.1.21

 

I'm teaching myself php and need some help with arrays and drop down menus

I've built and array containing state ids and state names.

  Example:

[1]Alabama [2]Alaska [3]Arizona [4]Arkansas [5]California and so on.

 

 

 

I have this section of code to build a dropdown menu from a record set, works fine.

 

<select name="listStates" id="listStates">

  <option value="">Select a state</option>

  <?php

    do { ?>

        <option value="<?php echo $row_getStates['state_id']?>"><?php echo $row_getStates['state_name']?></option>

        <?php

    } while ($row_getStates = mysql_fetch_assoc($getStates));

        $rows = mysql_num_rows($getStates);

        if($rows > 0) {

          mysql_data_seek($getStates, 0);

  $row_getStates = mysql_fetch_assoc($getStates);

        }

  ?>

</select

 

 

I now want to build the same menu with the array

 

I get this far and I'm stumped.

 

How do I define my array elements in the foreach loop?

 

 

<select name="listStatesArray" id="listStatesArray">

  <option value="">Select a state</option>

  <?php

    foreach ($arrayStates as $statesMenu) {

 

    ?>                                       

      <option value="<?php echo $statesMenu  (need ID here)?>"><?php echo $statesMenu  (need name here)?></option>

    <?php

    }

  ?>

</select>

 

Any help will be greatly appreciated

[Psycho]

<select name="listStatesArray" id="listStatesArray">
   <option value="">Select a state</option>
   <?php
     foreach ($arrayStates as $stateID => $stateValue) {
        echo "<option value=\"$stateID\">$stateValue</option>";
     }
   ?>
</select>

[jim.davidson]

That's what I needed.

 

Thank You