php filter

[chriscloyd]

I made a chat room with php and now im trying to make a bad word filter cna someone help me? not to code but to lead me in the right direction heres the script i have now thats not working

<?php
session_start();
mysql_connect('localhost','******','*****');
mysql_select_db('*****');
function filterBadWords($str){

// words to filter
$badwords=array( "fuck", "bitch", "ass", "a s s", "f u c k", "cunt", "pussy");

// replace filtered words with
$replacements=array( "&#()*@", "@^%(*!", "*&@&^@&@#" );

for($i=0;$i < sizeof($badwords);$i++){
  srand((double)microtime()*1000000); 
  $rand_key = (rand()%sizeof($replacements));
  $str=eregi_replace($badwords[$i], $replacements[$rand_key], $str);
}
return $str;
}
if (isset($_SESSION['thewayofthejew'])) {
$time = date('n/j/y g:i:s A');
$message = strip_tags($_POST['message']);
filterBadWords($message);
mysql_query("INSERT INTO chat (`user`, `message`, `time`) VALUES ('".$_SESSION['thewayofthejew']."', '".$str."', '".$time."')");
header("Location: index.php?page=chat");
}
?>

[The Little Guy]

Something like this?

<?php
$entered = $_POST['message'];

$words = array('/badword/','/another/','/words/');
$replay = array('bw','ano','wor');
echo preg_replace($word,$replay,$entered);
?>

[chriscloyd]

i got this error

 

Warning: preg_replace() [function.preg-replace]: Parameter mismatch, pattern is a string while replacement in an array. in /usr/home/www5965/public_html/jarred/sendchat.php on line 10