Show file content

[Maig]

I need to show the content of the file, the file is chosen in a form and so far I have...

 

if($_GET["username"] == "comp1920" && $_GET["password"] == "php")
{
$contents = file($_GET["course"]);

$array = split(",", $contents);
foreach($array as $item){
	echo "$item<br>";
}
}
else{
echo 'username/password combination is not correct, sorry';
}

 

But this does not work, I get an error, Array to String... What am I doing wrong? The file that I am trying to display is chosen in a form...

 

Thanks,

Maig

[sKunKbad]

urldecode() if the file name has a . in it.

[1bradillac]

If you're talking about a Directory (when you say file) then try scandir()

 

if($_GET["username"] == "comp1920" && $_GET["password"] == "php")
{
$contents = file($_GET["course"]);

$array = scandir($contents)
foreach($array as $item){
	echo "$item<br>";
}
}
else{
echo 'username/password combination is not correct, sorry';
}

[KrisNz]

$contents is an array already, thats what the file() function does. If you want to read a file into a string try file_get_contents().