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[SOLVED] need a second pair of eyes


RyanSF07

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Hi all,

 

I'm testing this

 

<a href \"http://$row[user_url]\">$row[user_name]</a>

 

and it's coming back as a link to the url of the present webpage rather than pulling the "users website url" from the data base.

 

The sql select statement says to pull * from the database. Thus, the row user_url should be coming up.

 

Any ideas?

 

Thanks,

Ryan

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i would do something like

 

 

$query = "SELECT * FROM database";
$result = mysql_query($query);

while ($line = mysql_fetch_array($result)) {

echo "<a href=\"http://".$line['user_url']."\">".$line['user_name']."</a>";

}

 

;-) try that but change the database name

Thanks Guys,

 

I tried adding the single quotes, but that produces a parse error. The username and other info all displays as it should. All I'm trying to do is pull the "user_url" too ...

 

Here is my select statment. looks similar to the one suggested:

$sql = "SELECT * FROM video, registered_users WHERE video.id = '$_GET[id]' AND video.user_id = registered_users.id";

//Register session key with the value
$_SESSION[get] = $_GET[id];
$query_result = mysql_query($sql);
$row = mysql_fetch_array($query_result);

 

thanks for your help!

ryan

try this:

 

/********************/
/* MODIFY TO YOUR OWN VALUES */
/********************/
$mshost=""; // mysql host
$mspass=""; // mysql super user password
$msuser=""; //mysql super user
$tbl_name=""; //Table name
$part1=""; //column Name
$part2=""; // What your wanting to select from the database
$dbname=""; // Database name

mysql_connect($mshost,$msuser,$mspass) or die(mysql_error());
mysql_select_db($dbname) or die(mysql_error());


$sql1=sprintf("SELECT * FROM $tbl_name WHERE $part1='$part2'");
$result1=mysql_query($sql1);
$row=mysql_fetch_array($result1);

echo "<a href \"http://www.yoursite.com/".$row[user_url]."\">".$row[user_name]."</a>";

?>

 

CODE NOT TESTED!

 

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