chris_rulez001 Posted June 26, 2007 Share Posted June 26, 2007 hi ive made a file uploader and i would like my file uploader to log whos uploaded which file and what file name, type, size it is. i would like it logging via mysql databases. can this be done? html code: <form action='file_upload.php' method='post' enctype='multipart/form-data'> <label for='file'>Filename:</label> <input type='file' name='file' id='file' /> <br/> <br /> <input type='submit' name='submit' value='Submit' /> </form> php code: <?php if ($_FILES["file"]["type"]; == "image/gif") || $_FILES["file"]["type"]; == "image/pjpeg") || $_FILES["file"]["type"]; == "image/png") && ($_FILES["file"]["size"] < 20000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("memberuploads/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "uploads/" . $_FILES["file"]["name"]); echo "Stored in: " . "memberuploads/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file"; } ?> Link to comment https://forums.phpfreaks.com/topic/57259-file-uploader/ Share on other sites More sharing options...
chris_rulez001 Posted June 26, 2007 Author Share Posted June 26, 2007 bump Link to comment https://forums.phpfreaks.com/topic/57259-file-uploader/#findComment-283137 Share on other sites More sharing options...
chris_rulez001 Posted June 27, 2007 Author Share Posted June 27, 2007 bump Link to comment https://forums.phpfreaks.com/topic/57259-file-uploader/#findComment-283920 Share on other sites More sharing options...
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