joshgarrod Posted June 27, 2007 Share Posted June 27, 2007 Hello, can someone shed some light on this please. it is a search script (obviously) that searches my stock database, however, it comes up with an error when you search for a phrase with more than one word. what is wrong, cud someone please help me. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Search for spares</title> <style type="text/css"> <!-- .style1 {font-family: Arial, Helvetica, sans-serif} --> </style> </head> <body> <h2 class="style1">Search</h2> <form action="<?=$PHP_SELF?>" method="post" name="search" class="style1"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="ID">Stock ID</option> <Option VALUE="StockNumber">Stock number</option> <Option VALUE="StockDescription">Stock description</option> </Select> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <p class="style1"> <? //This is only displayed if they have submitted the form if ($searching =="yes") { echo "<h2>Results</h2><hr>"; //If they did not enter a search term we give them an error if ($find == "") { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); //Now we search for our search term, in the field the user specified $find_array = explode(" ", $find); $find_sql = ""; // init foreach ($find_array as $temp) $find_sql .= "LIKE '%$temp%' OR "; $find_sql = substr($find_sql, 0, -3); // throw away last OR statement $data = mysql_query("SELECT * FROM stock WHERE upper($field) $find_sql"); //And we display the results while($result = mysql_fetch_array( $data )) { echo "<b>Stock ID: </b>"; echo $result['ID']; echo "<br>"; echo "<b>Stock number: </b>"; echo $result['StockNumber']; echo "<br>"; echo "<b>Stock description: </b>"; echo $result['StockDescription']; echo "<br>"; echo "<b>Price: </b>"; echo $result['ItemPrice']; echo "<br>"; echo "<hr>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </p> </body> </html> Quote Link to comment Share on other sites More sharing options...
Wuhtzu Posted June 27, 2007 Share Posted June 27, 2007 Can you please tell us what the error is (copy and paste it) and point out the line (If the error says "... on line 53" help us identify line 53) Quote Link to comment Share on other sites More sharing options...
joshgarrod Posted June 27, 2007 Author Share Posted June 27, 2007 ok here is the errors, Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/sto21/sites/www.stowmarketcaravans.co.uk/Search.php on line 58 Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/sto21/sites/www.stowmarketcaravans.co.uk/Search.php on line 76 full code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Search for spares</title> <style type="text/css"> <!-- .style1 {font-family: Arial, Helvetica, sans-serif} --> </style> </head> <body> <h2 class="style1">Search</h2> <form action="<?=$PHP_SELF?>" method="post" name="search" class="style1"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="ID">Stock ID</option> <Option VALUE="StockNumber">Stock number</option> <Option VALUE="StockDescription">Stock description</option> </Select> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <p class="style1"> <? //This is only displayed if they have submitted the form if ($searching =="yes") { echo "<h2>Results</h2><hr>"; //If they did not enter a search term we give them an error if ($find == "") { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "sgfh1", "ixfhfgh") or die(mysql_error()); mysql_select_db("sto21") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); //Now we search for our search term, in the field the user specified $find_array = explode(" ", $find); $find_sql = ""; // init foreach ($find_array as $temp) $find_sql .= "LIKE '%$temp%' OR "; $find_sql = substr($find_sql, 0, -3); // throw away last OR statement $data = mysql_query("SELECT * FROM stock WHERE upper($field) $find_sql"); //And we display the results while($result = mysql_fetch_array( $data )) { echo "<b>Stock ID: </b>"; echo $result['ID']; echo "<br>"; echo "<b>Stock number: </b>"; echo $result['StockNumber']; echo "<br>"; echo "<b>Stock description: </b>"; echo $result['StockDescription']; echo "<br>"; echo "<b>Price: </b>"; echo $result['ItemPrice']; echo "<br>"; echo "<hr>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </p> </body> </html> Quote Link to comment Share on other sites More sharing options...
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