[SOLVED] print 01 not 1 in a for loop

[awebbdesign]

I have the following..

 

for ($a = 01; $a < 13; $a++) {

 

<option value='$a'>$a</option>

 

}

 

however it starts at 1, ideally I need it to print...

01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 11, 12

 

I tried number_format but with no joy, any pointers?

 

 

[HuggieBear]

Something like this?

 

<?php
for ($a = 1; $a < 13; $a++){
   if ($a < 10){
      $a = "0" . $a;
   }
   echo "<option value='$a'>$a</option>\n";
}
?>

 

Regards

Huggie

[no_one]

You might want to try sprintf(..) to format a print string. (or printf());

 

$af = sprintf("%'02d",$a);

 

<option value='<?php echo $af; ?>'>.....

 

You can look it up, but here's a quick overview. % starts the type specifier, d = integer. '0 indicates you want the number padded (the ') with 0's  and the following 2 indicates you want it all printed 2 wide minimum, so that when you get into double digit numbers the padding will no longer be applied.

[bbaker]

if you need the output to look like this (with comma separation): 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 11, 12

 

<?php
for ($a = 1; $a < 13; $a++) {
$output[] = sprintf("%'02d",$a);
}
echo join(', ', $output);
?>

 

if you need the output for a drop down list

<select name="name">
<?php
for ($a = 1; $a < 13; $a++) {
$a = sprintf("%'02d",$a);
echo "<option value=\"$a\">$a</option>\n";
}
?>
</select>

[awebbdesign]

Cheers guys, I will learn more about this sprintf, many thanks