[SOLVED] glob() question for this code

[ballhogjoni]

I have this code below and it will pull each file in the folder and print it to the browser. My only problem is that there is a file named bottom_content.php that shows up and I dont want it too. Can some one show me how to make sure this file doesn't show up in my array or browser? Thanks in advance

 

<?php
foreach (glob("*.php") as $filename) {
echo "<a href=\"$PHP_SELF/articles/credit_repair/$filename\">".substr($filename,0,strlen($filename)-4)."</a> | "; 
}
?>

[effigy]

foreach (glob("*.php") as $filename) {
if ($filename == 'bottom_content.php') {
	continue;
}
echo '...'
}

[bbaker]

<?php
foreach (glob("*.php") as $filename) {
if ($filename != 'bottom_content.php') {
echo "<a href=\"$PHP_SELF/articles/credit_repair/$filename\">".substr($filename,0,strlen($filename)-4)."</a> | "; 
}
}
?>

[ballhogjoni]

Thank you, I found that it works with one file, but what if I would like to do multiple?

 

ex:

<?php
foreach (glob("*.php") as $filename) {
($filename == 'add_edit_cards.php' && $filename == 'config.php' && $filename == 'index.php') {
	continue;
}
echo "<a href=\"$PHP_SELF/articles/credit_repair/$filename\">$filename</a><br>";
}
?>

[no_one]

You'd want to use and or....

 

 

if( $filename == 'add_edit_cards.php' [b]||[/b] $filename == 'config.php' [b]||[/b] $filename == 'index.php' )
{
}

[effigy]

Make an array of exceptions and use in_array.

[ballhogjoni]

I am not to good with array's do mean something like this:

 

<?php
			foreach (glob("*.php") as $filename) {
				if (in_array($filename == 'add_edit_cards.php','config.php','index.php')) {
					continue;
				}
				echo "<a href=\"$PHP_SELF/articles/credit_repair/$filename\">$filename</a><br>";
			}
			?>

[no_one]

$noshow = array("file1","file2","file3");

 

foreach(...)

{

  if( in_array($filename,$noshow) )

  {

          continue;

  }

}

[ballhogjoni]

Thank you it worked great.