Foser Posted June 29, 2007 Share Posted June 29, 2007 Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\WAMP\www\Projects\LogiPlan\index.php on line 20 thats my error. this is my script: <title>Login Page</title> <?php //starting SESSION session_start(); //Lazy Login if ($_SESSION['LOGGEDIN'] == TRUE){ header("Location: /main/index.php");} //SQL Configuration file require("config.php"); //when pressed submit execute the FOLOWING if (isset($_POST['submit'])){ // USER TYPED INFORMATION $user = mysql_real_escape_string($_POST['username']); $password = sha1(md5($_POST['password'])); // Searching DB for username and password Match $result = mysql_query("SELECT * FROM user_info username = '$user' and password = '$password'"); if (mysql_num_rows($result) > 0){ // SETTING UP SESSIONS $_SESSION['LOGGEDIN'] = TRUE; $_SESSION['UNAME'] = $user; //Go To Member Control Panel if ($_SESSION['LOGGEDIN'] = TRUE){ header("Location: /main/index.php"); exit; }} // IF EVERYTHING ELSE IS FALSE EXECUTE THIS: else { echo "You have not entered the correct data. You may try again.";}} ?> <form name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <label>Username: <input type="text" name="username" id="username"> </label> <br> Password: <label> <input type="password" name="password" id="password"> </label> <br> <label> <input type="submit" name="submit" id="submit" value="submit"> </label> </form> thansk Quote Link to comment Share on other sites More sharing options...
hackerkts Posted June 29, 2007 Share Posted June 29, 2007 Maybe you will find some errors with your query, try mysql_error() Quote Link to comment Share on other sites More sharing options...
aim25 Posted June 29, 2007 Share Posted June 29, 2007 Try this, i had the same problem, but i dont remember how i fixed it. <?php $result = "SELECT * FROM user_info username = '$user' and password = '$password'"; ?> Quote Link to comment Share on other sites More sharing options...
Foser Posted June 29, 2007 Author Share Posted June 29, 2007 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= 'admin' and password = '55c3b5386c486feb662a0785f340938f518d547f'' at line 1 wow first time i see this error, seems like it does not know where to get the admin username from. but i checked my database everything is spelled correcly Quote Link to comment Share on other sites More sharing options...
no_one Posted June 29, 2007 Share Posted June 29, 2007 You forgot the WHERE in your select Select [values] from table WHERE [condition] Quote Link to comment Share on other sites More sharing options...
Foser Posted June 29, 2007 Author Share Posted June 29, 2007 hehe yea just found out came to tell u guys but you beat me to it. thanks guys Quote Link to comment Share on other sites More sharing options...
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