Jump to content

for() error?


ki

Recommended Posts

<select name="register_BirthdayYear"><?
for($i = date("Y") - 12; $i == date("Y") - 100; $i--) {
echo "<option value=\"".$i."\">".$i."</option>";
} ?>
</select>

im trying to make it go down from Current year - 12 then stop at current year - 100 then go down every year, but all it returns is null, any ideas?

Link to comment
Share on other sites

I am not sure why your for loop didn't work, but that is another way to do it.

 

 

edit... I know why..

<select name="register_BirthdayYear"><?
for($i = date("Y") - 12; $i == date("Y") - 100; $i--) { // on this line it should be $i != date("Y") - 100;
echo "<option value=\"".$i."\">".$i."</option>";
} ?>
</select>

 

Link to comment
Share on other sites

<select name="year">

 

<option value="">Year</option>

 

<?php for($i = date('Y') - 5, $min = $i - 95; $i >= $min; $i--): ?>

 

<option value="<?=$i?>"<?=(isset($_REQUEST['year']) && $_REQUEST['year'] == $i ? ' selected' : '')?>><?=$i?></option>

 

<?php endfor; ?>

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.