Jump to content

You have an error in your SQL syntax; check the manual that corresponds to ...


d22552000

Recommended Posts

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' `Crystal`=`Crystal`+, `Dueterium`=`Dueterium`+ WHERE `uname` = 'd22552000'' at line 1

 

$sql = "SELECT * FROM `accounts`";
$result = mysql_query($sql);

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
foreach($row as $user) {

	$sqla = "SELECT * FROM `galaxy` WHERE `Owner` = '" . $user . "'";
	$resulta = mysql_query($sqla);

	while($rowa = mysql_fetch_array($resulta, MYSQL_ASSOC))
	{
		$sqlb = "UPDATE `test`.`accounts` SET `Metal`=`Metal`+" . $row2['MetalIncome'] . ", `Crystal`=`Crystal`+" . $row2['CrystalIncome'] . ", `Dueterium`=`Dueterium`+" . $row2['DuerteriumIncome'] . " WHERE `uname` = '" . $user . "';";
		echo $row2['MetalIncome'];
		echo $row2['CrystalIncome'];
		echo $row2['DueteriumIncome'];
		mysql_query($sqlb) or die (mysql_error());
	}
}
}

 

What is wrong?

What is going on right here?

UPDATE `test`.`accounts`

 

Are you trying to update two tables at once? Or is the tables name "testaccounts" and for some reason you are trying to concate them together?

 

Look at the end of your query:

`uname` = '" . $user . "';";

 

You are closing it twice ";...take one out.

 

I'm surprised you aren't getting syntax errors for the above mistakes before you are getting an error from the executed query.

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.