Can i pass multiple values in a query string

[Lassie]

I need to pass  a couple of values in a query string. Is this possible.

I have the following code but get a parse error.

function display_categories($cat_array)
{
  if (!is_array($cat_array))
  {
     echo 'No categories currently available<br/>';
     return;
  }
  echo '<ul>';
  foreach ($cat_array as $row)
  {
    $url = 'show_cat.php?region_id='.($row['region_id']).country=.($row['country'])';
    $title = $row['region_desc'];

echo '<li>';
    do_html_url($url, $title); 
    echo '</li>';
  }    
  echo '</ul>';
  echo '<hr />';
  }

[tapos]

$url = 'show_cat.php?region_id='.($row['region_id']).country=.($row['country'])';

this should be

$url = 'show_cat.php?region_id='.($row['region_id']).'&country='.($row['country'])';

 

--

Tapos Pal

[Lassie]

Thanks Tapos.

I am now getting a parse error (Unepected t constant etc) on the next line. I cant see a problem with it.

Any ideas?

[jitesh]

Post

error

with

code

[jd2007]

try using this:

$url = 'show_cat.php?region_id='.($row['region_id'])&country=.($row['country'])';

 

pls tell me wheter it worked or not...if u get error, what is the error ?

 

Note: i used ampersand

[Lassie]

Hi thanks for coming back. I get a parse error for that line which is

unexpected'='in ect line 33.

I am alos getting a fatal error . Call to undefine function do_html_url() which has worked perfectly well until now.Code for that function is

function do_html_url($url, $title)
{
  // output URL as link and br
?>
  <a href="<?php echo $url; ?>"><?php echo $title; ?></a><br />
<?php
}

Thanks for your help

[jitesh]

$url = "show_cat.php?region_id=".$row['region_id']."&country=".$row['country'];

[jd2007]

ok...there was some bugs in fact..use this instead:

 

$url = "show_cat.php?region_id='.($row[region_id]).&country=.($row[country])";

 

does it work ? 

[Lassie]

Hi thanks for that. Yes it works.So far so good.I will plough on with the rest of it.

[Lassie]

sorry spoke too soon. i have no value in country. It should be a name.

[jd2007]

try this :

 

 

$url = "show_cat.php?region_id='.($row[region_id]).'&'.country=.($row[country]).' ";

 

hope it works...

[Lassie]

Thanks Jd both work.I forgot to amend my db query to retireve the country value.

Many thanks.

lassie

[jd2007]

you're welcome...if u need anything, message me...i'm always online...