Setting drop down based on 2d array

[jwhite68]

I have an array as follows:

 

$arr_subtype[0][0] = "Jam";
$arr_subtype[0][1] = "Custard";
$arr_subtype[1][0] = "Not applicable";
$arr_subtype[2][0] = "Pie";
$arr_subtype[2][1] = "Cake";
$arr_subtype[2][2] = "Sweet";

 

If the value of the first element is 0, I want to display Jam/Custard in the drop down, if the first element is 1, just display 'Not applicable' and if first element is 2, display the Pie,Cake and Sweet values in the drop down.

 

I also have values for the 2 array indexes in variables, based on when user has selected a value. So when the form is redisplayed, it displays the existing value.

$index1 and $index2 are the variables for the selected values.  Where $index1 is a higher level list earlier in the code.

 

The first entry will also display a 'Select type' initially, when the form is first displayed (before they have selected anything).

 

The code I need is something like:

 

select name="subtype" id="subtype" "<option value="" selected>Select type</option>
<?
foreach ($arr_subtype as $key => $value)
{
										if ($key==$index2) // display existing value if set as selected
            { 
										echo '<option value="'.$key.'" selected>'.$value.'</option>'; 
} 
else 
            { 
											echo '<option value="'.$key.'">'.$value.'</option>'; 
}
}
?>

 

I know this code isnt correct, and wondered if anyone code advise?

 

Its on an ADD form, that validates other form fields, and has to redisplay the drop downs with the previously selected values (ie remember previously entered values).

[Psycho]

select name="subtype" id="subtype">
<option value="">Select type</option>
<?php
foreach ($arr_subtype[$index1] as $indexVal => $optionVal)
{
    $selected=($index1==$indexVal)?' selected="selected"':'';
    echo "<option value=\"$indexVal\"$selected>$optionVal</option>";
}
?>