[SOLVED] Calculating time function

[ramli]

Hi im working on a invoice system. In this system i have to calculate with time and dates.Im searching to find a custom or php function that allows me to do this. it has t work somthing like this.

 

Adding Time

2007-06-14 + 2 days = 2007-06-16

2007-06-31 + 2 days = 2007-07-02

2007-06-11 + 1 month = 2007-07-11

2007-06-11 + 1 year = 2008-06-11

ect..

 

Telling Difference

2007-06-14 ~ 2007-06-16 = 2 Days

ect..

 

Deducting Time (-)

Same story for Time (00:00:00)

 

I cant seem to find a topic or function that does all this... Perhaps im looking in the wrong places if u can help me please do so. thanks in Advance.

 

 

[drewbee]

take a look at these functions

time() // Gets current timestamp

mktime() // Gets timestamp of given time based on paremters

strtotime() // returns timestamp of passed string ie "5 days ago"

[AbydosGater]

Just an idea to save you some time.. you could try use a timestamp instead of actual dates... and then have a converter that changes the timestamp to a date format..

 

Then when you want to add or remove the dates you just find a function (Cause there are a good few out there) that would timestamp1 - timestamp2 = difference... and then check the difference.. if its over however many seconds there is in one day and so on..

 

Andy

 

EDIT: Oh.. beaten to the mark! Sorry

[ramli]

if used this method

 

$date1 = "2007-06-16";
$date2 = "2007-06-18";

$covertdate1 = strtotime($date1);
$covertdate2 = strtotime($date2);


$differance = $covertdate2 - $covertdate1;

$result =  date("d-m-Y", $differance);

echo($result);

 

It outputs 03-01-1970 i want it to output 2 as if the difference is 2 day's what am i doing wrong ?

[drewbee]

 

$date1 = mktime(0,0,0, 6, 16, 2007);

$date2 = mktime(0,0,0, 6, 18, 2007);

 

$dif = $date2 - $date1;

 

You now have the SECONDS between the two dates.

 

Do some math and you can figure out how many years/months/days/hours/minutes/seconds etc are left.

[ramli]

Created a function that works

 

//--------------------------TCALC----------------------------//
//Get date from seconds
function TCALC($dateinsecs)
{

  if($dateinsecs >= 187200) 
  { 
  	$dateinsecs = floor($dateinsecs);
    $year = ($dateinsecs / 187200); 
  } 
  
  if($dateinsecs >= 15600) 
  { 
  	$dateinsecs = floor($dateinsecs);
    $month = ($dateinsecs / 15600); 
  } 
  
  if($dateinsecs >= 86400) 
  { 
  	$dateinsecs = floor($dateinsecs);
    $day = ($dateinsecs / 86400); 
  } 
  
  if($dateinsecs >= 3600) 
  { 
  	$dateinsecs = floor($dateinsecs);
    $hour = ($dateinsecs / 3600); 
  }
  
  if($dateinsecs >= 60) 
  { 
  	$dateinsecs = floor($dateinsecs);
    $minute = ($dateinsecs / 60); 
  }
  
  if($dateinsecs >= 0) 
  { 
  	$seconds = floor($dateinsecs);
  }
  
  $time_int = array('year'=>$year,'month'=>$month,'day'=>$day,'hour'=>$hour,'minute'=>$minute,'seconds'=>$seconds); 
  return $time_int;
}

 

$date1 = "2007-06-16";
$date2 = "2007-06-18";

$date1 = strtotime($date1);
$date2 = strtotime($date2);

$date = $date2 - $date1;
$dateview = TCALC($date);
echo($dateview['day']);

 

You know you will be returnd a day becouse you Deduct the dates from eachother

it will return 2 (days)