preg_replace help

[marcus]

I'm trying to make it so:

 

[profile=username] replaces with username(username)

 

username() is a function I have that links the "username" to that profile

 

$string = "[profile=marcus;]";

echo "Before: $string<br>\n";
echo "After: ";
echo preg_replace("[profile=(.*?);]",username("\\1"),$string);

 

I get:

 

 

Before: [profile=marcus;]

After: [marcus]

 

 

The after statement is producing a link to that profile with an image. The image identifies the user's level, the link is correct.

 

How would I remove the brackets on the start and the end of "[marcus]" ?

[effigy]

I'm confused at what you're trying to achieve on a step-by-step basis. Are you saying everything works fine, except the end result needs to remove the braces? Or are the braces the result of something not being processed correctly?

[marcus]

I don't want the braces, and the variable inside the username function is not passing correctly.

 

Username function does: [puts image on administrative level][link to profile]

 

I'm getting:

 

[frozenpic][link to profile]

 

Therefore the username isn't in existence.

[clearstatcache]

try ds....

preg_replace("/profile=(.*?);/",username("\\1"),$string);

[marcus]

I'm still getting the wrong image. I'm trying to get image "6", but I keep getting "4"

 

I also believe that the variable is NOT passing threw the username function.

 

I've tried returning the username value inside the function but it's blank.

[effigy]

You have two problems:

 

1. PREG requires delimiters.

2. [ and ] are metacharacters.

 

The [ and ] around your pattern are being considered delimiters and therefore not actually matching a pair of braces. You need to add a delimiter, then escape the braces in order to match them:

 

/\[profile=(.*?);\]/